When 25.0 grams of FeO react with 25.0 grams of Al, how many grams of Fe can be produced?

Which of the following is included in the measure of U.S. GDP?

finlep [7]

the value of increase in business inventories.

7 0

4 years ago

A given volume of methane diffuses in 20 seconds. How long will it take the same volume of hydrogen to diffuse under the same co

Airida [17]

The time taken for the same volume of methane gas to diffuse is 7.1 s.

<h3>Rate of gas diffusion</h3>

The rate at which a given mass of diffuses is inversely proportional to the molar mass of the gas.

$\frac{t_2}{t_1} = \sqrt{\frac{M_2}{M_1} }$

where;

M1 is the molar mass of methane (CH4) = 16 g
M2 is the molar mass of hydrogen as = 2
t1 is time taken for methane = 20 s
t2 is the time taken for hydrogen = ?

$\frac{t_2}{t_1} = \sqrt{\frac{M_2}{M_1} }\\\\\frac{t_2}{20} = \sqrt{\frac{2}{16} }\\\\\frac{t_2}{20} = \frac{\sqrt{2} }{4} \\\\t_2 = \frac{20\sqrt{2} }{4} \\\\t_2 = 5\sqrt{2} \\\\t_2 = 7.1 \ s$

Thus, the time taken for the same volume of methane gas to diffuse is 7.1 s.

Learn more about rate of gas diffusion here: brainly.com/question/26696466

6 0

2 years ago

Read 2 more answers

Biphenyl, C12H10,C12H10, is a nonvolatile, nonionizing solute that is soluble in benzene, C6H6.C6H6. At 25 ∘C,25 ∘C, the vapor p

cestrela7 [59]

Answer:

Vapour pressure of solution is 78.151 torr

Explanation:

Molar mass of biphenyl = 154.21 g

Molar mass of benzene = 78.11 g

19.2 g biphenyl = (19.2/154.21) moles of biphenyl = 0.125 moles of biphenyl

33.7 g of benzene = (33.7/78.11) moles of benzene = 0.431 moles of benzene

Total number of moles = (0.125+0.431) moles = 0.556 moles

Mole fraction of benzene in solution = (0.431/0.556) = 0.775

According to Roults law, vapour pressure of solution made from non-volatile solute = $(mole fraction of solvent in solution)\times (vapour pressure of pure solvent)$

Here solute is biphenyl and solvent is benzene

So, vapour pressure of solution = $(0.775\times 100.84)torr$ = 78.151 torr

8 0

3 years ago

Potassium sulfate has a solubility of 15g/100g water at 40 Celsius. A solution is prepared by adding 39.0g of potassium sulfate

nadya68 [22]

Answer:

5.25 grams of potassium sulfate will get crystallize out.

Explanation:

Solubility of potassium sulfate at 40 °C = 15 g/100 g

This means that at 40 °C 15 g of potassium sulfate will get completely dissolved in 100 of water.

39.0 g of potassium sulfate to 225 g water, carefully heating the solution.

Amount of potassium sulphate will get dissolve in 225 g of water at 40 °C will be:

$\frac{15g}{100g}$ × 225 = 33.75g

Amount of potassium sulfate precipitated out by the solution:

= 39.0 g-33.75 g = 5.25 g

At 40 °C 5.25 g of potassium sulfate will get precipitate out from the solution which means that solution is saturated.

Saturated solution are solution in which solute is dissolved in maximum amount. Further addition of solute results in precipitation of solute form the solution.

5.25 grams of potassium sulfate will get crystallize out.

(Hope this Helps can I pls have brainlist (crown)☺️)

8 0

3 years ago

You have 185 mL of an acid with an unknown concentration. To determine the concentration you decide to use a 0.85 M solution of

kondor19780726 [428]

Explanation:

The given data is as follows.

$M_{1}$ = ?, $M_{2}$ = 0.85 M