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I think the above conversion is an example of A.) ALPHA DECAY.
In Alpha decay, nucleus releases an alpha particle, Helium. When the alpha particle is released the remaining nucleus weighs less due to the decrease in neutrons and protons have also decreased in number.
Answer:
on the right side, because it is a product
Explanation:
photosynthesis is the chemical reaction with the help of which plants produce chemical energy with the help of light energy.
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The general standard for writing chemical reaction is that
- The chemical which are input to the process of chemical reaction are written on left hand side . They are known as reactant.
- The output of chemical reaction are written on right side. They are termed as product.
- Transition of reactant to product is shown by arrow.
Chemical reaction for photosynthesis is given by below equation
6CO2 + 12H2O + light ----------------> C6H12O6 + 6O2 + 6H2O
We can see that 6 molecules of light combines with 12 molecules of water to give one molecule of glucose and 6 molecules of both water and oxygen.
As, oxygen is the output of photosynthesis process, it is written on the right-hand side of equation and is product of this reaction.
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Thus, of the options given below for
In an equation for photosynthesis does oxygen belong
on the right side, because it is a product
Answer:
Explanation:
Hello!
In this case, since the formula for the calculation of molarity is defined in terms of moles and volume in liters as shown below:
Whereas the moles are computed by considering the molar mass of CaCO3 (100.09 g/mol):
Thus, we obtain:
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Answer:
The correct answer is 0.165 g NaCl.
Explanation:
The following is the precipitation reaction taking place between sodium chloride and silver nitrate:
NaCl (aq) + AgNO₂ (aq) ⇒ NaNO₃ (aq) + AgCl (s)
The complete ionic reaction of the reaction will be,
Na⁺ + Cl⁻ + Ag⁺ + NO₃⁻ ⇒ AgCl (s) + Na⁺ + NO₃⁻
Hence, the net ionic equation for the mentioned reaction is:
Ag⁺ (aq) + Cl⁻ (aq) ⇒ AgCl (s)
Thus, it can be witnessed that one mole of chloride ion is needed so that one mole of Ag⁺ ion get neutralized. There is a need to find the moles of silver ions present in the solution of AgNO₃ and then transform these moles to the moles of chloride ion. Ultimately, these moles can be converted to the concentration of sodium chloride needed.
The no. of moles of silver ions found in silver nitrate solution is,
(2.50 × 10² mL) × (0.0113 mol Ag⁺/1000 ml solution) = 2.83 × 10⁻³mol Ag⁺
Now the moles of chloride ions needed to precipitate the silver ions is,
(2.83 × 10⁻³ mol Ag⁺ ) × (1 mol Cl⁻/1 mol Ag⁺) = 2.825 × 10⁻³mol Cl⁻
The mass of sodium chloride needed for precipitating the silver ions will be,
mass of NaCl = (2.83 × 10⁻³ mol Cl⁻) × (1 mol NaCl / 1 mol Cl⁻) × (58.44 grams / 1 mol NaCl)
= 0.165 gram NaCl.