Answer:
+5
Explanation:
Let's consider the following balanced equation.
Mn(NO₃)₂ + 2 HCl --> MnCl₂ + 2 HNO₃
We can determine the oxidation number of N in (NO₃)₂²⁻ taking into account that the sum of the oxidation numbers of the elements present in a chemical species is equal to this overall charge. For this compound we know:
- The oxidation number of O is -2.
- The overall charge is 2-.
- We have 2 atoms of N and 2× 3 = 6 atoms of O.
2 N + 6 O = 2-
2 N + 6 (-2) = 2-
2 N = +10
N = +5
Matter and energy are conserved in nature through their use by biological systems, which is dedicated by the Law of conservation.
<h3>What does matter and energy conservation mean?</h3>
Matter and energy conservation indicate that organisms can not create or destroy these elements in nature.
Matter and energy conservation are fundamental for maintaining the state of equilibrium (homeostasis) of biological systems.
In conclusion, matter and energy are conserved in nature through their use by biological systems, which is dedicated by the Law of conservation.
Learn more about matter and energy here:
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Answer:
Explanation:
For a general equilibrium
aA +bB ⇔ cC + dD ,
the equilibrium constant is K = [C]^c [D]^d / [A]^a[B]^b.
Our reasoning here should be based on the fact that Q has the same expression as K, but is used when the system is not at equilibrium, and the system will react to make Q = K to attain it ( Le Chatelier´s principle ).
So with this in mind, lets answer this question.
1. False: Q can large or small but is not the value of the equilibrium constant, it will predict the side towards the equilibrium will shift to attain it.
2. False: Given the expression for the equilibrium constant, we know if K is small the concentrations of the reactants will be large compared to the equilibrium concentrations of the products.
3. False: when the value of K is large, the equilibrium concentrations of the products will be large and it will lie on the product side.
4. True: From our previous reasongs this is the true one.
5. False: If K is small, the equilibrium lies on the reactants side.
Answer:
403 mL
Explanation:
First, I will assume that the mole is 1, because you are not specifing this.
Now, with the innitial data, we need to get the pressure:
T = 65+273 = 338 K
V = 500 / 1000 = 0.5 L
Now if:
PV = nRT
Then:
P = nRT/V and V = nRT/P
Let's calculate the P:
P = 1 * 0.082 * 338 / 0.5 = 55.432 atm
The standard temperature is 0° C or 273 K so, the volume is:
V = 1 * 0.082 * 273 / 55.432
V = 0.40384 L or simply 403.84 mL
