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Vesna [10]
4 years ago
7

1. Point charges q 1 q 2 both of 22 nC are separated by a distance of 58 cm along a horizontal axis. Point a is located 40 cm fr

om and cm from q 1 q 2 . What is the magnitude and direction of the electric field at point a?
A)1900 N/C, directed toward q2
B)4900N / C , directed toward q1
C)7300 N/ C, directed toward q1
D)1900N / C , directed toward q 1

2. The diagram shows an electric field generated by two oppositely-charged flat plates. Where is the electric field uniform?

A)Near the ends of each plate
B)At distances about 1 m or greater from either plate
C)throughout the region shown in the diagram
D)between the two plates

3. Object A has a charge of + q . If it were replaced with an object that has a charge of -q, how would the electric field at point P be affected?

A)The magnitude would decrease, while the direction stays the same.
B)The magnitude would increase, while the direction stays the same.
C)The direction would reverse, while the magnitude stays the same.
D)The direction would rotate clockwise by 90 degrees , while the magnitude stays the same

4. As shown in the diagram, points P and R form a straight line with point charge q. Point P is located 25 cm from q, and point R is located 75 cm from q. Let E p equal the magnitude of the electric field at point P. What is the magnitude of the electric field at point R?

A)Ep/3
B)Ep/9
C)Ep/50
D)Ep/25

5. Points P and R are equidistant to charged object A, and they are positioned on opposite sides of (point) the object. Compared to the electric field at point P theelectric field at point R is

A)equal in magnitude and direction
B)equal in magnitude, perpendicular in direction
C)smaller in magnitude, equal in direction
D)equal in magnitude, opposite in direction

6. Point P is located 1.7 m from fixed point charge The electric field vec E at point P is 8.6 * 10 ^ (- 2) N/C, directed away from the point charge. What is the magnitude of q? Let the electrostatic constant k=8.99*10^ 9 N* m^ 2 / C^ 2

A)2.8 x 10^-11 C
B)4.8 x 10^-11 C
C)-4.8 x 10-11 C
D)1.5 x 10 ^-10 C

7. Point P is located 58 cm to the right of a fixed point charge of 6.7*10^ -16 C. What is the direction and magnitude of the electric field at point P due to this charge? Let the electrostat constant k = 8.99 * 10 ^ 9 * N * m ^ 2 / (C ^ 2)

8.8 * 10 ^ (- 5) * N/C, to the right
2.4 * 10 ^ (- 6) * N/C , to the left
1.2*10^ (-5) * N/C, to the left
1.8*10^ (-5) N/C, to the right

8. A Van de Graaff generator causes a total charge q to build up on a metal sphere of radius Which variable does not affect the electric field at a distance R from the center of the metal sphere? Assume R> r

A)the distance R from the center of the metal sphere
B)the magnitude of the charge q
C)the radius r of the metal sphere
D)the sign of the charge q

9. A scientist fixes a test charge q’ to point P and then measures the electrostatic force it experiences there. She then calculates the magnitude of the electric field by applying the equation vec E = vecF^prime/vec q^prime. Which change to her procedure would vary the value of vec E that she calculates?

A)keep the test charge in the same location, but alter its charge from q^prime to -q^1.
B)keep the charge on the test charge the same, but move the test charge to a different position farther away.
C)keep the test charge in the same location, but after its charge from q^prime to 2q^prime

10. q 1 q 2 Point charge of 30 nC is separated by 50 cm from point charge q2 of -45nC. As shown in the diagram, point a is located 30 cm from q1 and 20 cm from q2. What are the magnitude and direction of the electric field at point a? Let the electrostatic constant k = 8.99 * 10 ^ 9 * N m ^ 2 / (C ^ 2)

A)7000 N/C, directed to q2
B)13,000 N/C, directed to q1
C)13,000 N/C, directed to q2
D)7000 N/C, directed to q1

Physics
1 answer:
Bess [88]4 years ago
3 0

Answer:

1.B

2.D

3.idk

4.B

5.idk

6.A

7.idk

8.C

9.B

10.idk

Explanation:

I literally failed to get the answers also idk = i dont have the questions that you do.

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A person walks 45 m East and then walks 39 m at an angle 40◦ North of East. What is the magnitude of the total displacement? Ans
vredina [299]

Answer:

r = 78.95 m

Explanation:

given,

Person Walk in east, r₁ = 45 m

Then he walk, r₂= 39 m in the direction of 40◦ North of East.

writing the total displacement in x- direction

 r₁ₓ  = 45 m

 r₂ₓ = 39 cos 40°

  r₂ₓ = 29.87 m

total displacement in x-direction

rₓ = r₁ₓ + r₂ₓ

rₓ = 45 + 29.87

rₓ = 74.87 m

displacement in y-direction

r_{1y} = 0 m

r_{2y} = 39 sin 40°

r_{2y} = 25.07 m

total displacement in y- direction

  r_y = 25.07 m

using Pythagoras theorem for the magnitude calculation

 r = \sqrt{r_x^2 + r_y^2}

 r = \sqrt{74.87^2 +25.07^2}

        r = 78.95 m

The magnitude of total displacement is equal to 78.95 m.

8 0
3 years ago
A sled and rider (combined mass of 69 kg) finish a downhill run with a speed of 30 m/s, then enter a flat (horizontal) area wher
NARA [144]

Answer:

Distance that sled move while slowing down= 195.65m

Explanation:

Distance traveled by sled after slowing down=S

acceleration at the start= -2.3 m/s2

initial speed u=30m/s

final speed=v

By using the equation

v^{2} =u^{2} +2as\\

Final speed is zero.

Therefore;

0=30^{2} +2*(-2.3)*s\\2*2.3s=30^{2} \\s=30^{2} /(2*2.3)\\s=195.65 m

6 0
3 years ago
Represent the following sentence as an algebraic expression, where "a number" is the
agasfer [191]

Answer:

2 (x+3)

Explanation:

8 0
3 years ago
Please help!<br> If an object has a mass of 500 g and floats, what volume of water must it displace?
mafiozo [28]

It must displace at least 500 milliliters (0.5 liter) of water, in order to float in water.

4 0
3 years ago
Based on the graph of kinetic energy given (gray curve in the graphing window), sketch a graph of the baseball's gravitational p
chubhunter [2.5K]

1) Physical principles:

a) Total mechanical energy = kinetic energy + potential energy.

b) Total mechanical energy is conserved (neglecting external forces, like drag and friction)

2) Notation:

a) Total mechanical energy: ME.

b) Kinetic energy: KE

c) Gravitational potential energy: PE

∴ ME = KE + PE = constant

3) Solution:

a) Since, ME is conserved, it is constant and would be represented in the graph by a horizontal line.

b) At start (t = 0), the ball has only KE, so KE =ME = E and PE = 0

c) As the time goes, the ball gains altitude (PE increases) and loses speed (KE decreases).

d) PE increases from 0 to a maximum value. In the graph that happens at t = 2s.

At that point, KE = 0, and PE = ME.

That is the point of highest altitude and where the speed is zero.

d) From t = 2 seg, the ball starts to lose altitude, then the ball loses PE, and gains KE.

Just before reaching the ground, at t = 4s, the ball has the same initial KE and PE as at t = 0: KE = ME and PE = 0.

The PE may be sketched on the same graph along with the KE and the ME.

The graph is attached. The red line is the ME and the blue line is the PE.

Note that at any point in the graph PE + KE = ME.

5 0
4 years ago
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