Work done
- FscosØ
- 208.4(161.5)cos32
- 33656.6cos32
- 28542.4J
Work done by kinetic friction:-
- 0.455(197)(9.8)
- 878.423N
The correct answers are:
(1) Force on the object.
(2) 4000 N
Explanations:
(1) According to Newton's second law, force (F) is directly proportional to the acceleration (a) of an object:
F ∝ a
(or F = ma)
As the force (F) on the object increases, the acceleration of that object will also increase. One thing to remember here is that the (net) force must be in the same direction as the acceleration produced by that force to get the maximum increase in the object's acceleration.
Hence, the correct answer is "force on the object."
(2) Again, by using Newton's second law, we can find the net force as follows:
Mass = m = 2000kg
acceleration = a = 2 m/s^2
Since,
F = ma --- (A)
Plug in the values in equation (A):
F = 2000 * 2 = 4000 N
Hence, the correct answer is 4000N.
<span>
No. of e- at a instant through given area is = total charge passing per
unit time/charge of e-
using i=q/t=(no.of e-(n))(1.6*10^-19)= 10
n=6.3*10^19 </span>
Answer:
Randell using a public computer is vulnerable to theft.
