3 years ago

Explain how tidal forces are causing Earth to slow down.

1 answer:

6 0

Answer: The tidal forces exerted by the moon are directly associated with the earth's rotation. Due to the strong gravitational pull of the moon, the tidal bulging appears on both the sides on earth and these are region of high tide, and there is gradual rise and fall of sea level.

Because of these tidal effect, the earth is able to rotate only once in each of the orbital period.

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A beam of red light is made to pass through two slits that are 3.55 E-3 meters apart. On a screen 2.25 meters away from the slit

JulsSmile [24]

I am assuming you know the relation obtained between slit width, distance of screen from slits, distance of interference pattern obtained on the screen from the center and the wavelength of monochromatic light used in Young's Double Slit experiment.
λ = $\frac{y*d}{D} = \frac{3.55*10^{-3}*1.25*10^{-4} }{2.25} = 1.97*10^{-7} m$
λ ~ 1.97 ×10⁻⁷m

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3 years ago

To calculate work done on an object, _____. A. multiply the force in the direction of motion by the distance the object moved B.

o-na [289]

I believe your answer would be B, hope it helps

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3 years ago

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If a stone with an original velocity of 0 is falling from a ledge and takes 8 seconds to hit the ground, what is the final veloc

sergey [27]

I believe the answer is C - 78.4 m/s.

8 0

2 years ago

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1- O telhado de um grande galpão mede 40 m por 75 m e é feito de zinco, cujo coeficiente de dilatação térmica linear vale 3.10^-

Minchanka [31]

Answer:q

Explanation:

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3 years ago

Find the frequency if the period is 15 us.

Sav [38]

Answer:

The frequency is $0.667$ × $10^{6}$ $Hz$ .

Explanation:

Period is defined as the time taken by any element to attempt one complete oscillatory motion in one second.
Frequency is the number of complete oscillations made in one second.

Frequency and period are inversely proportional to each other.

In mathematical term: $frequency$ = $\frac{1}{period}$ .
As we are given, $period$ = $15$ × $10^{-6}$ $s$ .
We can easily calculate frequency as: $f\\$ = $\frac{1}{15. 10^{-6} }$
So frequency is $f$ = $0.667$ × $10^{6}$ $Hz$ .

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3 years ago