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astraxan [27]
1 year ago
9

A 0.2 kg baseball is struck with a force of 100 n from a baseball bat. according to newton's 2nd law, what can we determine abou

t the ball's motion while it is in contact with the bat? question 2 options: it has a speed of 500 m/s it has a speed of 0.002 m/s it has an acceleration of 20 m/s/s it has an acceleration of 500 m/s/s it has a speed of 20 m/s it has an acceleration of 0.002 m/s/s
Physics
1 answer:
Black_prince [1.1K]1 year ago
7 0

1. According to Newton's second law of motion, when ball contact with bat we can find the acceleration.

acceleration = 500 m/s^{2}

According to Newton's second law,

Force = mass * acceleration

acceleration = Force/Mass

acceleration = 100n/0.2kg

acceleration = 500 m/s^{2}

Learn more about acceleration here:

brainly.com/question/15295474

#SPJ4

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A car starting from rest has a constant acceleration of 4 meters per second per second. How fast will it be going in 5 seconds?
irinina [24]

Answer:

18 m

Explanation:

Given : vo = 0 m/s ; t = 3 s; a = 4 m/s^2 ; d = ? m ; average velocity = ? m/s ; fonal velocity = ? m/s

solving for the final velocity, v

v = a * t

v = 4 m/s^2 * 3 s

v = 12 m / s

Solving for the average velocity. avg v

avg v = (vo + v) / 2

avg v = (0 m / s + 12 m/s) / 2

avg v = 6 m / s

Solving for the distance traveled after 3 s

d = avg v * t

d = 6 m / s * 3 s

d = 18 meters

In the first 3s the car travels 18 meters.

4 0
2 years ago
The process of changing the energy of a system by means of force. Force * Diatance
Dmitry_Shevchenko [17]
This is known as work
7 0
3 years ago
0.002 written in scientific notation
Oliga [24]

Answer:0,002 = 2 x 10⁻³

Explanation:

0,002 = 2 / 1000 = 2 / 10³ = 2 x 10⁻³

3 0
3 years ago
1. Na jaką wysokość wzniesie się piłka kopnięta pionowo w górę z prędkością 20 m/s ? 2. Piłka o masie 20 dag spada z wysokości 1
Tresset [83]

Answer:

its gonn abe 23

Explanation:

6 0
3 years ago
Read 2 more answers
(III) A baseball is seen to pass upward by a window with a vertical speed of If the ball was thrown by a person 18 m below on th
Ghella [55]

Answer:

<em><u>Assuming that the vertical speed of the ball is 14 m/s</u></em> we found the given values:

a) V₀ = 23.4 m/s

b) h = 27.9 m

c) t = 0.96 s

d) t = 4.8 s

 

Explanation:

a) <u>Assuming that the vertical speed is 14 m/s</u> (founded in the book) the initial speed of the ball can be calculated as follows:  

V_{f}^{2} = V_{0}^{2} - 2gh

<u>Where:</u>

V_{f}: is the final speed = 14 m/s

V_{0}: is the initial speed =?

g: is the gravity = 9.81 m/s²

h: is the height = 18 m

V_{0} = \sqrt{V_{f}^{2} + 2gh} = \sqrt{(14 m/s)^{2} + 2*9.81 m/s^{2}*18 m} = 23.4 m/s  

b) The maximum height is:

V_{f}^{2} = V_{0}^{2} - 2gh

h = \frac{V_{0}^{2}}{2g} = \frac{(23. 4 m/s)^{2}}{2*9.81 m/s^{2}} = 27.9 m

c) The time can be found using the following equation:

V_{f} = V_{0} - gt

t = \frac{V_{0} - V_{f}}{g} = \frac{23.4 m/s - 14 m/s}{9.81 m/s^{2}} = 0.96 s

d) The flight time is given by:

t_{v} = \frac{2V_{0}}{g} = \frac{2*23.4 m/s}{9.81 m/s^{2}} = 4.8 s

         

I hope it helps you!    

3 0
3 years ago
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