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gizmo_the_mogwai [7]
3 years ago
5

If two point sources of light are being imaged by this telescope, what is the maximum wavelength λ at which the two can be resol

ved if their angular separation is 3.0×10−5 radians? Express your answer in nano.
Physics
1 answer:
Alex3 years ago
6 0

This question is incomplete.Here is complete one

Consider a telescope with a small circular aperture of diameter 2.0 centimeters. If two point sources of light are being imaged by this telescope, what is the maximum wavelength (lambda) at which the two can be resolved if their angular separation is 3.0x10^-5 radians? Express your answer in nanometers

Answer:

λ =492nm

Explanation:

Given Data

diameter=2.0 cm

angular separation=3.0x10^-5 radians

λ=?

Solution

sin(theta) = 1.22 x λ /D

λ=(0.02×sin(3.0×10⁻⁵))/1.22

λ=492nm

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A parallel-plate capacitor is charged by connecting it across the terminals of a battery. If the battery remains connected and t
Tanya [424]

Answer:

The voltage ( or potential difference) V increases while the charge Q decreases.

Explanation:

The capacitance C of a capacitor is defined as the measure to which the capacitor can store charges. For a parallel-plate capacitor it is given by the following relationship;

C=\frac{\epsilon_o\epsilon_rA}{d}............(1)

where A is the surface area of the plates, d is their distance of separation, \epsilon_o is the permittivity of free space and \epsilon_r is relative permittivity.

Also, the capacitance of a capacitor can be expressed in the form of equation (2)

C=\frac{Q}{V}...................(2)\\

where Q is the charge stored and V is the potential difference.

By combining (1) and (2) and making d the subject of formula, we obtain the following;

d=\frac{\epsilon_o\epsilon_rAV}{Q}............(3)

By observing (3), it is seen that the distance d of separation between the plates is directly proportional to the potential difference V and inversely proportional to the charge stored Q. This implies that an increase in the distance d of separation will bring about an increase the the voltage or potential difference V and a decrease in the charge Q.

6 0
3 years ago
if a bullet fired beneath the water, straight up, breaks through the surface at a speed of 25m/s, how high will the bullet be af
Doss [256]

Answer:

32 m and -2.4 m/s

Explanation:

Given:

v₀ = 25 m/s

t = 2.8 s

a = -9.8 m/s²

Find: Δy, v

Δy = v₀ t + ½ at²

Δy = (25 m/s) (2.8 s) + ½ (-9.8 m/s²) (2.8 s)²

Δy = 31.6 m

v = at + v₀

v = (-9.8 m/s²) (2.8 s) + 25 m/s

v = -2.44 m/s

Rounded to two significant figures, the bullet reaches a height of 32 m and a velocity of -2.4 m/s.

8 0
3 years ago
After a chemical reaction, the atomic nuclei are _________.
sleet_krkn [62]

After a chemical reaction, the atomic nuclei are unchanged. (C)


The nucleii don't know a thing about the outside world during

physical or chemical processes ... not until NUCLEAR things

happen.

4 0
3 years ago
A stalled car is being pushed up a hill at constant velocity by three people. the net force on the car is
frosja888 [35]
I think you need more information like the force of gravity and the force of the three people. Once you combine the two, however, you should get the net force.
6 0
3 years ago
A parallel RLC resonant circuit has a resistance of 200 Ω. If it is known that the bandwidth is 80 rad/s and the lower half-powe
d1i1m1o1n [39]

Answer:

L= 3.6mH

C =9.9 microfarad

Explanation:

Resonant frequency fr

fr = fl + 1/2 BW

fr = 800+ 1/2×80

=800+40

=840 rad/s

Bandwidth (BW)

BW = fr/Q

Q = quality factor

Q= fr/ BW

Q = 840/80

Q= 10.5

Quality factor = R/Xl

Xl = inductive reactance

Xl = R/Q

Xl = 200/10.5

Xl = 19.05 ohms

Xl =2πfL

L= Inductance

L = Xl /2πf

L =19.05/5278.56

L= 3.6mH

Capacitor C

1= fr^2 × 4π^2LC

C = 1/fr^24π^2L

C = 1/100307.5

C= 9.9microfarad

5 0
3 years ago
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