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Law Incorporation [45]
3 years ago
6

One mole of an ideal gas expands isothermally from 0.01 m3 to 0.05 m3. The final pressure of gas is 1.2 atm. [15 Marks] determin

e the work done on its surrounding find the initial pressure of the gas a. b.
Physics
1 answer:
erik [133]3 years ago
4 0

Answer:

Initial pressure = 6 atm. Work = 0.144 J

Explanation:

You need to know the equation P1*V1=P2*V2, where P1 is the initial pressure, V1 is the initial volume, and P2 and V2 are the final pressure and volume respectively. So you can rearrange the terms and find that (1.2*0.05)/(0.01) = initial pressure = 6 atm. The work done by the system can be obtained calculating the are under the curve, so it is 0.144J

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The gravity of earth depends on the _____ from its ____ . as this _____increase, the magnitude of the gravity _____.
Anna [14]
<span>The gravity of earth depends on the magnetism from its core. as this magnetism increases, the magnitude of the gravity increases.</span>
3 0
3 years ago
Strontium has density of 2.64 g/cm3 and crystallizes with the face-centered cubic unit cell. Calculate the radius of a strontium
pantera1 [17]

Answer:

The radius of strontium atom is

2.14 E-8cm

Explanation:

Go through the attached file for a comprehensive detailed explanation.

6 0
3 years ago
What is the tangential velocity of a record player which makes 11 revolutions in 20 seconds?
slava [35]

Answer:

The tangential velocity of a rotating object is:

v = r*w

where r is the radius, and w is the angular velocity.

w = 2*pi*f

where f is the frequency.

We know that the record plater does 11 revolutions in 20 seconds, then it does:

11 rev/20s = 0.55 rev/s = f

then we have:

w = 2*pi*0.55 s^-1 = 2*3.14*0.55 s^-1 = 3.454 s^-1

The radius of a record player is really variable, it is around 10 inches, so i will use r = 10in, which is the rotating part of the record player.

then the tangential velocity is:

v = 10in*3.454 s^-1 = 34.54 in/s

7 0
3 years ago
What is the electric potential energy of a charge that experiences a force of 3.6 x 10^-4N when it is 9.8 x 10^-5 from the sourc
Levart [38]
The electric potential energy of the charge is equal to the potential at the location of the charge, V, times the charge, q:
U=qV
The potential is given by the magnitude of the electric field, E, times the distance, d:
V=Ed
So we have
U=qEd (1)
However, the electric field is equal to the electrical force F divided by the charge q:
E= \frac{F}{q}
Therefore (1) becomes
U=Fd
And if we use the data of the problem, we can calculate the electrical potential energy of the charge:
U=Fd=(3.6 \cdot 10^{-4}N)(9.8 \cdot 10^{-5} m)=3.53 \cdot 10^{-8} J
7 0
4 years ago
A dad pushes tangentially on a small hand-driven merry-go-round and is able to accelerate it from rest to a frequency of 18 rpm,
puteri [66]

Answer:

F = 176.175 N

Explanation:

given,  

radius of merry - go - round = 2.7 m

mass of the disk = 800 kg  

speed of the merry- go-round = 18 rpm  

                                                 = 18 \dfrac{2\pi }{60}

                                                 = 1.88 rad/s

time = 13 s

mass of two children = 25 kg  

ω = ω₀ + α t

1.88 = 0 + α(13)

α = 0.145 rad/s²

we know

τ = I α

so,

I = \dfrac{1}{2}MR^2+ 2 MR^2  

I = \dfrac{1}{2}\times 800 \times 2.7^2+ 2\times 25\times 2.7^2

I = 3280.5 kg.m^2  

τ = I α

τ = 3280.5 x 0.145

τ = 475.67 N m

τ = F x r

475.67 = F x 2.7

F = 176.175 N

4 0
3 years ago
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