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Law Incorporation [45]
3 years ago
6

One mole of an ideal gas expands isothermally from 0.01 m3 to 0.05 m3. The final pressure of gas is 1.2 atm. [15 Marks] determin

e the work done on its surrounding find the initial pressure of the gas a. b.
Physics
1 answer:
erik [133]3 years ago
4 0

Answer:

Initial pressure = 6 atm. Work = 0.144 J

Explanation:

You need to know the equation P1*V1=P2*V2, where P1 is the initial pressure, V1 is the initial volume, and P2 and V2 are the final pressure and volume respectively. So you can rearrange the terms and find that (1.2*0.05)/(0.01) = initial pressure = 6 atm. The work done by the system can be obtained calculating the are under the curve, so it is 0.144J

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HURRY WILL GIVE BRAINLIEST
andrey2020 [161]

The amount of energy needed to melt the ice is 1670 J

Explanation:

The amount of thermal energy needed to completely melt a certain amount of solid substance (already at melting point) is given by

Q=m\lambda_f

where

m is the amount of the substance

\lambda_f is the specific latent heat of fusion of the substance

Here, the mass of the ice is

m = 5 g = 0.005 kg

And the specific latent heat of fusion of ice is

\lambda_f = 334,000 J/kg

Assuming that the ice is already at melting point, the thermal energy needed to melt the ice is

Q=(0.005)(334,000)=1670 J

Learn more about specific heat:

brainly.com/question/3032746

brainly.com/question/4759369

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8 0
3 years ago
A periodic wave of frequency f and speed v travel what distance in one period?
maw [93]
I think the answer is b
4 0
3 years ago
Antonina throws a coin straight up from a height of
vichka [17]

Answer:

s=vt-\frac{1}{2}gt^2

Explanation:

We could use the following suvat equation:

s=vt-\frac{1}{2}gt^2

where

s is the vertical displacement of the coin

v is its final velocity, when it hits the water

t is the time

g is the acceleration of gravity

Taking upward as positive direction, in this problem we have:

s = -1.2 m

g=-9.8 m/s^2

And the coin reaches the water when

t = 1.3 s

Substituting these data, we can find v:

v=\frac{s}{t}+\frac{1}{2}gt=-\frac{1.2}{1.3}+\frac{1}{2}(-9.8)(1.3)=-7.3 m/s

where the negative sign means the direction is downward.

5 0
3 years ago
I need help with question two
zaharov [31]
I can't see numbers here, so here are all the answers:
1) the frequency is c/λ = 3e8/556e-9 = 5.39e14Hz
2) light travels at <span>299,792,458 m/s.  So in nanoseconds it's 0.299792458m.  This is about 1/3 of a meter which is about one foot.
3) length is L = ct = (</span>299,792,458 m/s)(6e-15) = 1.799e-6m or 1.799μm

6 0
3 years ago
distance travelled = (ii) State the equation linking average speed, distance moved and time taken. v=¢ t​
gulaghasi [49]

Average speed = total distance/total time.

5 0
2 years ago
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