Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.
<h3>What is Iron (II) Oxide ? </h3>
The formula of the Iron II oxide is FeO. Common name of Iron (II) Oxide is Ferrous Oxide. Iron (II) Oxide is a black colored powder. The mineral form of Iron (II) oxide is known as Wustite. Iron (II) Oxide is used as a pigment. It is also used to make dyes.
<h3>What is Iron (III) Oxide ? </h3>
The formula of the Iron (III) Oxide is Fe₂O₃. Common name of Iron (III) Oxide is Ferric oxide. Iron (III) Oxide appears as Red-Brown solid. It is also known as Hematite. Iron (III) oxide is used as pigments. It is used in dental composites , cosmetics. It is also used to apply the final polish on metallic jewellery.
Thus from the above conclusion we can say that Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.
Learn more about the Iron (II) Oxide here: brainly.com/question/14143857
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Answer:
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<em><u>A</u></em><em><u>N</u></em><em><u>S</u></em><em><u>W</u></em><em><u>E</u></em><em><u>R</u></em></h2>
The second one would be one of the application of an endothermic reaction as because endothermic reaction always have the heat in the process to mix the reactants and form the products as here in a burning wood when the wood is supplied with heat then it change into products as ashes and smoke fumes So here due to the heat is involved to form the products thats the reaction is endothermic reaction.
Hope it helps
Answer:
χH₂ = 0.4946
χN₂ = 0.4130
χAr = 0.0923
Explanation:
The total pressure of the mixture (P) is:
P = pH₂ + pN₂ + pAr
P = 443.0 Torr + 369.9 Torr + 82.7 Torr
P = 895.6 Torr
We can find the mole fraction of each gas (χ) using the following expression.
χi = pi / P
χH₂ = pH₂ / P = 443.0 Torr/895.6 Torr = 0.4946
χN₂ = pN₂ / P = 369.9 Torr/895.6 Torr = 0.4130
χAr = pAr / P = 82.7 Torr/895.6 Torr = 0.0923
The answer is in the bladder.
a pure compound because an element is untouched and is just itself
