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liq [111]
2 years ago
5

Draw the major organic substitution product(s) for (2R,3S)-2-bromo-3-methylpentane reacting with the given nucleophile. Indicate

the stereochemistry, including H\'s, at each stereogenic center. Omit any byproducts.

Chemistry
1 answer:
Ede4ka [16]2 years ago
6 0

Answer:

The final product of the reaction is (<em>2S,3S</em>)-2-ethoxy-3-methylpentane.

Explanation:

The given reaction undergoes S_{N}2  mechanism in which the nucleophile attacks the backside and it is substituted by the elimination of bromine.

Due to the backside attack of nucleophile , the inverse in stereo-chemistry is observed.

After the substitution of ethoxy group, the configuration is assigned according to the priority it shows clock wise direction(R) - configuration.

When hydrogen faces the front side , it results shows inverse configuration i.e, S- configuration.

The chemical reaction is as follows.

 

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What volume will 1.12 moles of nitrogen gas occupy at STP
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Explanation:

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How many grams of Co are needed to react with an excess of fe203 to produce 156.2 g FE? show your work.
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7 0
3 years ago
Read 2 more answers
HC2H3O2 (aq) + H2O (l) ⇔ C2H3O2- (aq) + H3O+ (aq) Ka = 1.8 x 10-5
marin [14]

The concentration of [H3O⁺]=2.86 x 10⁻⁶ M

<h3>Further explanation</h3>

In general, the weak acid ionization reaction  

HA (aq) ---> H⁺ (aq) + A⁻ (aq)  

Ka's value  

\large {\boxed {\bold {Ka \: = \: \frac {[H ^ +] [A ^ -]} {[HA]}}}}

Reaction

HC₂H₃O₂ (aq) + H₂O (l) ⇔  (aq) + H₃O⁺ (aq) Ka = 1.8 x 10⁻⁵

\tt Ka=\dfrac{[C_2H_3O^{2-}[H_3O^+]]}{[HC_2H_3O_2]}}\\\\1.8\times 10^{-5}=\dfrac{0.22\times [H_3O^+]}{0.035}

[H₃O⁺]=2.86 x 10⁻⁶ M

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