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frozen [14]
3 years ago
9

How many milliseconds are there in 3.5 seconds

Chemistry
2 answers:
madam [21]3 years ago
8 0
There are 3500 milliseconds.
azamat3 years ago
5 0
There are 3,500 milliseconds in 3.5 seconds. Hope this helps!
You might be interested in
Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p
Butoxors [25]

Answer:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

BiO_3^-\rightarrow Bi^{3+}

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

(Bi^{5+}O_3)^-\rightarrow Bi^{3+}

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Then, we accommodate the waters to obtain:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Best regards!

7 0
3 years ago
Write a variable expression that represents the following word phrase: three more than two times the difference of x and one.​
Inga [223]

Convert the wordphrase to expression

\\ \rm\longmapsto 2(x-1)+3

\\ \rm\longmapsto 2x-2+3

\\ \rm\longmapsto 2x+1

5 0
3 years ago
Read 2 more answers
Examples of solid mixtures
elixir [45]
Salad, a bag of different colored pebbles or sand, etc
6 0
3 years ago
Identify the balanced chemical equation that represents a single displacement reaction.
UNO [17]

3H₂SO₄ + 2Al₂(SO₄)₃  → Al₂(SO₄)₃ + 3H₂ is the balanced chemical equation that represents a single displacement reaction.

<h3>What is a balanced chemical equation?</h3>

The equation in which the number of atoms of all the molecules is equal on both sides of the equation is known as a balanced chemical equation.

3H₂SO₄ + 2Al₂(SO₄)₃  → Al₂(SO₄)₃ + 3H₂

In this type of reaction, one substance is replacing another:

A + BC  →  AC + B

In a single displacement reaction, atoms replace one another based on the activity series. Elements that are higher in the activity series. Also, if the element that is to replace the other in a compound is more reactive the reaction will occur. If it is less reactive, there will be no reation.

In the first equation, fluorine is more reactive than bromine. Therefore, bromine cannot replace bromine.

In the second equation, the displacement is between hydrogen and aluminium. Hydrogen is lower in the activity series, this implies that aluminium will replace it.

Hence, 3H₂SO₄ + 2Al₂(SO₄)₃  → Al₂(SO₄)₃ + 3H₂ is the balanced chemical equation that represents a single displacement reaction.

Learn more about the displacement reaction here:

brainly.com/question/15052184

#SPJ1

8 0
2 years ago
For the following reaction, KcKc = 255 at 1000 KK.
bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

                           CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

Initial conc.      0.1550      0.173           0

At eqm.          (0.1550-x)  (0.173-x)         x

As we are given:

K_c=255

The expression for equilibrium constant is:

K_c=\frac{[COCl_2]}{[CO][Cl_2]}

Now put all the given values in this expression, we get:

255=\frac{(x)}{(0.1550-x)\times (0.173-x)}

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

5 0
3 years ago
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