Answer: Ф = 17.2657 ≈ 17°
Explanation:
we simply apply ET =0 about the ending of the rod
so In.g.L/2sinФ - In.a.L/2cosФ = 0
g.sinФ - a.cosФ = 0
g.sinФ = a.cosФ
∴ tanФ = a/g
Ф = tan⁻¹ a / g
Ф = tan⁻¹ ( 10 / 32.17405)
Ф = tan⁻¹ 0.31080948777
Ф = 17.2657 ≈ 17°
Therefore the angle of rotation of the rod during this acceleration is 17.2657 ≈ 17°
Answer:
b) in a direction that makes its potential energy decrease.
Explanation:
- As the electric field has the direction that would take a positive test charge under its sole influence, the positive test charge, will have an increase in its kinetic energy.
- Due to the conservation of energy, in absence of non-conservative forces, this increment must be equal and opposite to the change in electric potential energy, which will be always negative, independent of the sign of the charge.
Denser materials tend to be closer to earths center due to their mass gravity is shown by the equation mg
Which stands for mass x gravity.
Answer:
The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.
Explanation:
Given that,
Mass of softball = 0.220 kg
Speed = 5.5 m/s
(a). We need to calculate the velocity of the target ball
Using conservation of momentum
....(I)
The velocity approach is equal to the separation of velocity
(b). We need to calculate the mass of the target ball
Now, Put the value of v₂ in equation (I)
Hence, The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.
