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natka813 [3]
3 years ago
15

Why is tungsten used as a filament in a bulb?

Physics
1 answer:
Viktor [21]3 years ago
7 0

Answer:

because of tungsten's high melting point

Explanation:

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A longitudinal wave is observed. Exactly 6 crests are observed
valentinak56 [21]
The speed of the wave is 1.58 meters per second (or 1.584 if you don’t round it).
You multiply wavelength by frequency to get the speed of a wave.
2.4 times 0.66 = 1.548 meters per second.

If you didn’t have the frequency before hand, you would just divide the 6 crests by the 9.1 seconds.
3 0
2 years ago
Please hurry!!!!!!!.......
elixir [45]

Answer:

B

Explanation:

D is nonsense. The current keeps coming through all lights.

A is wrong. The exact opposite happens. More bulbs more resistance.

C is wrong. More resistance less current, not more.

So your answer is B because the voltage drop in each decreases when there are more bulbs.

5 0
3 years ago
Read 2 more answers
True false according to current atomic theory electrons are in fixed locations
Amanda [17]

That's <em>false.</em>  According to current atomic theory and quantum mechanics, an electron is always PROBABLY SOMEWHERE in a fuzzy foggy area around the nucleus of the atom, and that's all we can <u>ever</u> say about it.  There's no way to even TELL where the electron is, even if we <u>had</u> the technology to see things that small.

4 0
3 years ago
It takes 6 sec for a stone to fall the the bottom of a mineshaft. calculate the
Stels [109]
Ok so this is simple projectile motion problem.

if we have an object falling in free fall it is subject to gravity of -9.80m/s^2

so it says it takes 6 sec to fall and we know initial velocity was zero so we know that h=vt+1/2gt^2 so we get h=0+1/2*9.80*6^2 = 176.4m 

so solving for final speed we get KE=PE = 1/2mv^2=mgh = 1/2v^2=gh so 
v=sqrt(2*g*h) = sqrt(2*9.8*176.4m) = 58.8m/s final speed when it hits the ground


hope this helps you! Thanks!!

8 0
3 years ago
The velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in
vivado [14]

The force the escaping gas exerts of the rocket is 10.42 N.

<h3>Force escaping gas exerts</h3>

The force the escaping gas exerts of the rocket is calculated as follows;

F = m(v - u)/t

where;

  • m is mass of the rocket
  • v is the final velocity of the rocket
  • u is the initial velocity of the rocket
  • t is time of motion

F = (0.25)(40 - 15)/0.6

F = 10.42 N

Thus, the force the escaping gas exerts of the rocket is 10.42 N.

Learn more about force here: brainly.com/question/12970081

#SPJ1

7 0
2 years ago
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