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natka813 [3]
3 years ago
15

Why is tungsten used as a filament in a bulb?

Physics
1 answer:
Viktor [21]3 years ago
7 0

Answer:

because of tungsten's high melting point

Explanation:

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Question 8 of 10
-BARSIC- [3]

Answer:

The correct answer is the Convex lens. An image is formed when a ray of light coming from a point intersects at another point. The image is formed by the real intersection of light. The image is formed by the virtual intersection of Light.

here is the site : textbook.com

3 0
2 years ago
Why doesnt food have energy
Nataly_w [17]
Food has calories which feeds your bones in your body from eating away your muscles, it doesn’t have “energy” on the other hand pop and drinks do.
3 0
3 years ago
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Julie is cycling at a speed of 3.4 meters/second. If the combined mass of the bicycle and Julie is 30 kilograms, what is the kin
Anon25 [30]
Velocity=3.4m/sec
Mass=30kg
so kinetic energy=1/2mv^2
=1/2×30×3.4×3.4
=15×3.4×3.4
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=173.4 kg m per second square
6 0
3 years ago
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13. A transformer has a primary coil with 600 turns and a secondary coil with 300 turns. If the output voltage is 320 volts, wha
vivado [14]
His is a step down transformer since n(primary) is greater than n(seconcary). You relate the input voltage with the ouput voltage with the following equation: 

<span>Vout = n2/n1*Vin (n2/n1 is essentially your 'transfer function' that dictates what a specified input would produce) </span>

<span>Solving the equation: </span>

<span>Vin = Vout*n1/n2 = (320V)*(600/300) = 640 V </span>

<span>This is checked by seeing if Vin is greater than Vout, which it is for a step down transformer.</span>
5 0
3 years ago
A 0.49 m copper rod with a mass of 0.15 kg carries a current of 13 A in the positive y direction. Let upward be the positive dir
Helen [10]

Answer:

Magnetic field, B = 0.23 T          

Explanation:

Given that,

Length of the copper rod, L = 0.49 m

Mass of the copper rod, m = 0.15 kg

Current in rod, I = 13 A (in +ve y direction)

When the rod is placed in magnetic field, the magnetic force is balanced by its weight such that :

BIL=mg\\\\B=\dfrac{mg}{IL}\\\\B=\dfrac{0.15\times 9.8}{13\times 0.49}\\\\B=0.23\ T

So, the magnitude of the minimum magnetic field needed to levitate the rod is 0.23 T.

6 0
3 years ago
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