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wolverine [178]
1 year ago
6

14) A race car accelerates from rest to a velocity of 41 m/s in 480 m. What is the acceleration of the race car?

Physics
1 answer:
natka813 [3]1 year ago
8 0

Answer:

Explanation:

V₀ = 0 m/s

V = 41 m/s

S = 480 m

___________

a - ?

Distance traveled:

S =  (V² - V₀²) / (2*a)

Acceleration :

a = (V² - V₀²) / (2*S)

a = (41² - 0²) / (2*480) = 1.75 m/s²

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Answer:

a) 29.36 m

b) 2.44 s

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Explanation:

t = Time taken

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s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

b)

v=u+at\\\Rightarrow 0=24-9.81\times t\\\Rightarrow \frac{-24}{-9.81}=t\\\Rightarrow t=2.44 \s

Time taken by the ball to reach the highest point is 2.44 seconds

a)

s=ut+\frac{1}{2}at^2\\\Rightarrow s=24\times 2.44+\frac{1}{2}\times -9.81\times 2.44^2\\\Rightarrow s=29.35\ m

The highest point reached by the ball above its release point is 29.36 m

c) Total height is 3+29.35 = 32.35 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 32.35=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{32.35\times 2}{9.81}}\\\Rightarrow t=2.57\ s

The ball reaches the ground 2.57 seconds after reaching the highest point

d)

v=u+at\\\Rightarrow v=0+9.81\times 2.57\\\Rightarrow v=25.2117\ m/s

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While standing on a bridge 40.0 m above the ground, you drop a stone from rest. when the stone has fallen 3.80 m, you throw a se
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Given: distance 1 d₁ = 40 m;  distance 2 d₂ = 3.8 m   g = -9.8 m/s²

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