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denis23 [38]
3 years ago
6

The longest passenger liner ever built was the France, 66,348 tons and 315.5 long. Suppose its front end passes the edge of a pi

er at a speed of 2.10 m/s while the ship is accelerating uniformly at 0.03 m/s^2. At what speed will the back end of the vessel pass the pier?
Physics
1 answer:
Kaylis [27]3 years ago
5 0

Answer:

The back end of the vessel will pass the pier at 4.83 m/s

Explanation:

This is purely a kinetics question (assuming we're ignoring drag and other forces) so the weight of the boat doesn't matter. We're given:

Δd = 315.5 m

vi = 2.10 m/s

a = 0.03 m/s^2

vf = ?

The kinetics equation that incorporates all these variables is:

vf^2 = vi^2 + 2aΔd

vf = √(2.1^2 + 2(0.03)(315.5))

vf = 4.83 m/s

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on a aircraft carrier a jet is slowed from 105 mph to a stop in 2 seconds. What is the rate of deceleration?
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105/2 = 52.5/1

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6 0
3 years ago
When a warm air mass collides with a cold air mass, the warm air mass rises above the cold air mass leading too:
nikdorinn [45]

Answer: It leads to a front. A front is.., I don't know how to explain it, so I'll add a picture. Fronts are made out of clouds and usually bring rain. So the answer is C: The formation of clouds and rain.

Explanation:

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3 years ago
Write about the similarities and differences between kinetic and potential energy. Include specific, real world example in your
lord [1]

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Energy is transformed from potential to kinetic and vice versa

Explanation:

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The most characteristic and real example is that of a pendulum at one end, as can be seen in the attached image.

When the pendulum is located at the top end, as shown in Figure 1, at that point the maximum potential energy will be held. Then the pendulum is released and when it passes through the reference point and its height is zero, with respect to that point, all potential energy will have become kinetic energy in the same way at this point the maximum speed of the pendulum will be set.

8 0
3 years ago
For the different values given for the radius of curvature RRR and speed vvv, rank the magnitude of the force of the roller-coas
nirvana33 [79]

Explanation:

The force of the roller-coaster track on the cart at the bottom is given by :

F=\dfrac{mv^2}{R}, m is mass of roller coaster

Case 1.

R = 60 m v = 16 m/s

F=\dfrac{(16)^2m}{60}=4.26m\ N

Case 2.

R = 15 m v = 8 m/s

F=\dfrac{(8)^2m}{15}=4.26m\ N

Case 3.

R = 30 m v = 4 m/s

F=\dfrac{(4)^2m}{30}=0.54m\ N

Case 4.

R = 45 m v = 4 m/s

F=\dfrac{(4)^2m}{45}=0.36m\ N

Case 5.

R = 30 m v = 16 m/s

F=\dfrac{(16)^2m}{30}=8.54m\ N

Case 6.

R = 15 m v =12 m/s

F=\dfrac{(12)^2m}{15}=9.6m\ N

Ranking from largest to smallest is given by :

F>E>A=B>C>D

5 0
3 years ago
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