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4 years ago

Please help with this question.

Physics

1 answer:

EastWind [94]4 years ago

4 0

Answer:

41.16 Joules

Explanation:

Potential energy at a given instant is a function of mass and height of an object. The formula is

$E_p = mgh = 2.80kg\cdot 9.8\frac{m}{s^2}\cdot 1.50m = 41.16 J$

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An angle has a value of 2.2 radians. Find its value in degrees.

Irina18 [472]

Answer:

The value of 2.2 radians in degree is 126.11°.

Explanation:

Given that,

Angle = 2.2 radians

We need to calculate the value in degrees

We know that,

$1\ radians = \dfrac{180}{\pi}$

$2.2\ radians = \dfrac{180}{3.14}\times2.2$

$2.2\ radians = 126.11^{\circ}$

Hence, The value of 2.2 radians in degree is 126.11°.

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3 years ago

How long would the night be on June 21 in Fairbanks, Alaska?

Kaylis [27]

Answer:

21.49 hrs

Explanation:

it is the longest day of daylight due to Alaska being closest to the au. at the time

7 0

3 years ago

2 diferencias y 2 similitudes entre la actividad física y el ejercicio físico.

blondinia [14]

Answer:

En el deporte, la persona que lo práctica tiene que adecuarse a él, por el contrario cuando hablamos de actividad física el objetivo pasa por programar, dosificar y adecuar en entrenamiento a las características, necesidades y objetivos de cada persona.

6 0

3 years ago

Positive Charge is distributed along the entire x axis with a uniform density 12 nC/m. A proton is placed at a position of 1.00

lions [1.4K]

Answer:

b. $\Delta KE = 390 eV$

Explanation:

As we know that the electric field due to infinite line charge is given as

$E =\frac{\lambda}{2\pi \epsilon_0 r}$

here we can find potential difference between two points using the relation

$\Delta V = \int E.dr$

now we have

$\Delta V = \int(\frac{\lambda}{2\pi \epsilon_0 r}).dr$

now we have

$\Delta V = \frac{\lambda}{2\pi \epsilon_0}ln(\frac{r_2}{r_1})$

now plug in all values in it

$\Delta V = \frac{12\times 10^{-9}}{2\pi \epsilon_0}ln(\frac{1+5}{1})$

$\Delta V = 216ln6 = 387 V$

now we know by energy conservation

$\Delta KE = q\Delta V$

$\Delta KE = (e)(387V) = 387 eV$

3 0

3 years ago

how long does it take an acorn to hit the ground after dropping from the branch of a tree 12.5 m high?

Grace [21]

The right formula to use is: T^2= 2d/g
where T= time taken
d = 12.5m
g = is a constant and is equal to 9.8m/s
therefore, T^2 = 2*12.5/9.8
Using the values above, the time taken for the acorn to reach the ground is 1.59 second
T = 1.59 S

6 0

4 years ago