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viktelen [127]
2 years ago
15

Atomic physicists usually ignore the effect of gravity within an atom. To see why, we may calculate and compare the magnitude of

the ratio of the electrical force and gravitational force between an electron and a proton separated by a distance of 1 m.
1. What is the magnitude of the electrical force?
The Coulomb constant is 8.98755 x 10^9 N*m^2/C^2 , the gravitational constant is 6.67259 x 10^11 m^3 /kg*s^2 , the mass of a proton is 1.67262 x 10^-27 kg, the mass of an electron is 9.10939 x 10^−31 kg, and the elemental charge is 1.602 x 10^-19 C. Answer in units of N.
Physics
1 answer:
puteri [66]2 years ago
7 0

Explanation:

The electrical force between charges is given by :

F_e=\dfrac{kq_eq_p}{r^2}

q_e\ and\ q_p are charge on electron and proton respectively.

F_e=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1^2}\\\\F_e=2.3\times 10^{-28}\ N

The Gravitational force between masses is given by :

F_G=\dfrac{Gm_em_p}{r^2}

m_e\ and\ m_p are masses of electron and proton respectively.

F_G=\dfrac{6.67\times 10^{-11}\times 9.1\times 10^{-31}\times 1.67\times 10^{-27}}{1^2}\\\\F_G=1.01\times 10^{-67}

Ratio of electrical to the gravitational force is :

\dfrac{F_e}{F_G}=\dfrac{2.3\times 10^{-28}\ N}{1.01\times 10^{-67}\ N}\\\\\dfrac{F_e}{F_G}=2.27\times 10^{39}

Hence, this is the required solution.

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elixir [45]

Answer:

a --> true, b --> false, c --> true, d -->false

Explanation:

a) since it stays floating the gravity force and the upqards push is the same

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3 years ago
The work function for tungsten metal is 4.52eV a. What is the cutoff (threshold) wavelength for tungsten? b. What is the maximum
Tanya [424]

Answer: a) 274.34 nm; b) 1.74 eV c) 1.74 V

Explanation: In order to solve this problem we have to consider the energy balance for the photoelectric effect on tungsten:

h*ν = Ek+W ; where h is the Planck constant, ek the kinetic energy of electrons and W the work funcion of the metal catode.

In order to calculate the cutoff wavelength we have to consider that Ek=0

in this case  h*ν=W

(h*c)/λ=4.52 eV

λ= (h*c)/4.52 eV

λ= (1240 eV*nm)/(4.52 eV)=274.34 nm

From this h*ν = Ek+W;  we can calculate the kinetic energy for a radiation wavelength of 198 nm

then we have

(h*c)/(λ)-W= Ek

Ek=(1240 eV*nm)/(198 nm)-4.52 eV=1.74 eV

Finally, if we want to stop these electrons we have to applied a stop potental equal to 1.74 V . At this potential the photo-current drop to zero. This potential is lower to the catode, so this  acts to slow down the ejected electrons from the catode.

5 0
2 years ago
WILL GIVE BRAINLIEST!!!
Annette [7]

Answer:

Explanation:

Divergent Boundary

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3 years ago
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If you're having trouble understanding this, think of it like how the particles in water move compared to how the particles in ice move. The particles in water are free flowing and can move wherever they want. If they get colder, they won't move as much, and eventually they'll stop flowing around, forming a solid and staying colder than the water will get.
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2 years ago
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