Answer:
The greatest acceleration the man can give the airplane is 0.0059 m/s².
Explanation:
Given that,
Mass of man = 85 kg
Mass of airplane = 109000 kg
Distance = 9.08
Coefficient of static friction = 0.77
We need to calculate the greatest friction force
Using formula of friction
Where, m = mass of man
g = acceleration due to gravity
Put the value into the formula
We need to calculate the acceleration
Using formula of newton's second law
Put the value into the formula
Hence, The greatest acceleration the man can give the airplane is 0.0059 m/s².
Answer:
Distance covered to top of the hill was : 1.755 km
Explanation:
Initial velocity = 35 km/hr
Acceleration = 2.0 km/hr²
Time taken to accelerate = 3 minutes = 3/60 hours = 1/20 hours
Formula for acceleration : a = Δv /t
v-u/t ---where u is initial velocity , v is final velocity and t is time taken for acceleration
v- 35 / 0.05 = 2
v = 35.10 km/h
Formula for distance is product of speed and time
Distance covered = 35.10 * 0.05 = 1.755 km
The weight of the box is 50x9.8 = 490 N. The force of friction is 100N. F= μΝ so coefficient = 100/490 = 0.20
The total power delivered by the battery if the lightbulbs are connected is 9V^2/R
<h3>Power of a battery</h3>
The formula for calculating the power of a battery is expressed according to the equation;
Power = v^2/RT
where
R is the total resistance
v is the voltage or emf
If there are 3 identical lightbulbs, each having constant resistance R, then;
1/RT = 1/R + 1/R + 1/R
1/RT = 3/R
RT = R/3
The voltage drop across each lightbulbs will be the same for parallel connection, hence;
Power = 3V^2/(R/3)
Power = 9V^2/R
Hence the total power delivered by the battery if the lightbulbs are connected is 9V^2/R
Learn more on power here: brainly.com/question/24858512
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