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mylen [45]
3 years ago
6

Rosa is riding her bike at 15 mph toward school. Select all of the following statements that correct describe her motion.

Physics
2 answers:
kirill115 [55]3 years ago
5 0

1, 2 & 4 are going to be the the correct answer for the question

Alika [10]3 years ago
5 0

All but the third one are correct.

Hope this helps.

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A slinky forms it’s third harmonic standing wave when the input frequency is 24 Hz. What is the fundamental frequency of the sli
jarptica [38.1K]

Answer: The fundamental frequency of the slinky = 8Hz

An input frequency of 28 Hz will not create a standing wave

Explanation:

Let Fo = fundamental frequency

At third harmonic,

F = 3Fo

If F = 24Hz

24 = 3Fo

Fo = 24/3 = 8Hz

If an input frequency = 28 Hz at 3rd harmonic

Let find the fundamental frequency

28 = 3Fo

Fo = 28/3

Fo = 9.33333Hz

Since Fo isn't a whole number, it can't create a standing wave

6 0
3 years ago
Playing soccer on a beach will require more effort because the sand causes a great deal of _______ to the ball.
34kurt

Answer:

I believe the answer to be B

Explanation:

If you were playing on grass, the ball would be able to roll around much easier rather than it to be on sand. If it's wrong I am so sorry

5 0
2 years ago
Read 2 more answers
How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 4.00
klio [65]

Explanation:

Let us assume that the separation of plate be equal to d and the area of plates is 9 \times 10^{-4} m^{2}. As the capacitance of capacitor is given as follows.

            C = \frac{\epsilon_{o}A}{d}

It is known that the dielectric strength of air is as follows.

               E = 3 \times 10^{6} V/m

Expression for maximum potential difference is that the capacitor can with stand is as follows.

                       dV = E × d

And, maximum charge that can be placed on the capacitor is as follows.

               Q = CV

                   = \frac{\epsilon_{o} A}{d} \times E \times d

                   = \epsilon_{o}AE

                   = 8.85 \times 10^{-12} \times 3 \times 10^{6} \times 4 \times 10^{-4}

                   = 1.062 \times 10^{-8} C

or,                = 10.62 nC

Thus, we can conclude that charge on capacitor is 10.62 nC.

5 0
3 years ago
Two long, parallel wires separated by 3.50 cm carry currents in opposite directions. The current in one wire is 1.55 A, and the
vaieri [72.5K]

Answer:

Therefore,

The magnitude of the force per unit length that one wire exerts on the other is

\dfrac{F}{l}=2.79\times 10^{-5}\ N/m

Explanation:

Given:

Two long, parallel wires separated by a distance,

d = 3.50 cm = 0.035 meter

Currents,

I_{1}=1.55\ A\\I_{2}=3.15\ A

To Find:

Magnitude of the force per unit length that one wire exerts on the other,

\dfrac{F}{l}=?

Solution:

Magnitude of the force per unit length on each of @ parallel wires seperated by the distance d and carrying currents I₁ and I₂ is given by,

\dfrac{F}{l}=\dfrac{\mu_{0}\times I_{1}\times I_{2}}{2\pi\times d}

where,

\mu_{0}=permeability\ of\ free\ space =4\pi\times 10^{-7}

Substituting the values we get

\dfrac{F}{l}=\dfrac{4\pi\times 10^{-7}\times 1.55\times 3.15}{2\pi\times 0.035}

\dfrac{F}{l}=2.79\times 10^{-5}\ N/m

Therefore,

The magnitude of the force per unit length that one wire exerts on the other is

\dfrac{F}{l}=2.79\times 10^{-5}\ N/m

7 0
3 years ago
Read 2 more answers
Supposing d(t) is known to have value D,
creativ13 [48]

Answer:

  • The procedure is: solve the quadratic equation for t.

Explanation:

This question assumes uniformly accelerated motion, for which the distance d a particle travels in time t is given by the general equation:

  • d(t)=d_0+v_0t+at^2/2

That is a quadratic equation, where the independent variable is the time t.

Thus, the procedure that will find the time t at which the distance value is known to be D is to solve the quadratic equation for t.

To solve it you start by changing the equation to the general form of the quadratic equations, rearranging the terms:

  • (a/2)t^2+v_0t+(d_0-D)=0

Some times that equation may be solved by factoring, and always it can be solved by using the quadratic formula:

  • t=\frac{-b+/-\sqrt{b^2-4ac} }{2a}

Where:

a=-a/2\\ \\ b=v_0\\ \\ c=d_0-D

That may have two solutions. Some times one of the solution makes no physical sense (for example time cannot be negative) but others the two solutions are valid.

5 0
3 years ago
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