Answer:
Explanation:
Given that:
mass of stone (M) = 0.100 kg
mass of bullet (m) = 2.50 g = 2.5 ×10 ⁻³ kg
initial velocity of stone (
) = 0 m/s
Initial velocity of bullet (
) = (500 m/s)i
Speed of the bullet after collision (
) = (300 m/s) j
Suppose we represent 
to be the velocity of the stone after the truck, then:
From linear momentum, the law of conservation can be applied which is expressed as:
∴
The magnitude now is:
Using the tangent of an angle to determine the direction of the velocity after the struck;
Let θ represent the direction:
KE=1/2 m v^2
KE= .5 x 2kg x 15m/s to the 2nd power
KE=225 km/s
First, let's put 22 km/h in m/s:
Now the radial force required to keep an object of mass m, moving in circular motion around a radius R, is given by
The force of friction is given by the normal force (here, just the weight, mg) times the static coefficient of friction:
Notice we don't use the kinetic coefficient even though the bike is moving. This is because when the tires meet the road they are momentarily stationary with the road surface. Otherwise the bike is skidding.
Now set these equal, since friction is the only thing providing the ability to accelerate (turn) without skidding off the road in a line tangent to the curve:
Answer:
weight = 25*10 =250 N
Explanation:
g must be given in units of m/s^2
The weight of any type of body will be the product of his mass by the gravity
where:
m =mass [kg]
F = force [N] or [kg*m/s^2]
g = acceleration [m/s^2]
