You have 20 g of a buckyball (C20) .

How many Sr2+ ions are present in 0.314 moles of Sr3(PO4)2?

zubka84 [21]

Answer:

5.67x10²³ ions

Explanation:

By looking at the molecular formula, we can tell that there are three Sr²⁺ ions per Sr₃(PO₄)₂ molecule.

We convert Sr₃(PO₄)₂ moles into Sr₃(PO₄)₂ molecules by using Avogadro's number:

0.314 moles * 6.023x10²³ = 1.89x10²³ molecules

Finally we multiply that number by 3 in order to convert Sr₃(PO₄)₂ molecules to Sr²⁺ ions:

1.89x10²³ * 3 = 5.67x10²³ ions.

8 0

3 years ago

Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or

Ahat [919]

Answer :

Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

Rules for Oxidation Numbers are :

The oxidation number of a free element is always zero.
The oxidation number of a monatomic ion equals the charge of the ion.
The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
The oxidation number of oxygen (O) in compounds is usually -2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

Now we have to determine the oxidation state of the elements in the compound.

(a) $H_2SO_4$

Let the oxidation state of 'S' be, 'x'

$2(+1)+x+4(-2)=0\\\\x=+6$

Hence, the oxidation state of 'S' is, (+6)

(b) $Ca(OH)_2$

Let the oxidation state of 'Ca' be, 'x'

$x+2(-2+1)=0\\\\x=+2$

Hence, the oxidation state of 'Ca' is, (+2)

(c) $BrOH$

Let the oxidation state of 'Br' be, 'x'

$x+(-2)+1=0\\\\x=+1$

Hence, the oxidation state of 'Br' is, (+1)

(d) $ClNO_2$

Let the oxidation state of 'N' be, 'x'

$-1+x+2(-2)=0\\\\x=+5$

Hence, the oxidation state of 'N' is, (+5)

(e) $TiCl_4$

Let the oxidation state of 'Ti' be, 'x'

$x+4(-1)=0\\\\x=+4$

Hence, the oxidation state of 'Ti' is, (+4)

(f) $NaH$

Let the oxidation state of 'Na' be, 'x'

$x+(-1)=0\\\\x=+1$

Hence, the oxidation state of 'Na' is, (+1)

4 0

3 years ago

How many grams are in 0.90 mol Pd?*

maria [59]

Mass of Pd = 95.78 g which is close the the variant E) 95.89

Explanation:

To calculate the number of moles of palladium (Pd) we use the following formula:

number of moles = mass / atomic weight

mass = number of moles × atomic weight

mass of Pd = 0.90 × 106.42

mass of Pd = 95.78 g

Learn more about problems with number of moles:

brainly.com/question/3262

4 0

4 years ago

Because of its high reactivity which element is never found three in nature? O, F, N, or Ne

marshall27 [118]

The answer is F, or Fluorine.

Because of Fluorine's high reactivity, it is never found in nature.

The answer is F.

7 0

3 years ago

Read 2 more answers

Which would usually influence a reaction rate more? OH os O H&S O Neither H nors

bagirrra123 [75]

Answer:

As the average kinetic energy increases, the particles move faster and collide more frequently per unit time and possess greater energy when they collide. Both of these factors increase the reaction rate. Hence the reaction rate of virtually all reactions increases with increasing temperature

HOPE THIS HELPED!!!!!!!!!!!!!! XDDDDD

8 0

3 years ago