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andriy [413]
3 years ago
7

How many moles of co2 can be produced by the complete reaction of 1.53 g of lithium carbonatewith excess hydrochloric acid (bala

nced chemical reaction is given below)? li2co3(s) + 2hcl(aq) --> 2licl(aq) + h2o(l) + co2(g?
Chemistry
2 answers:
nlexa [21]3 years ago
7 0
Moles of Li2CO3 = 1.53/73.891 = 0.0207 mole
Since HCl is in excess, amount of CO2 will depend on the limiting reagent which is Li2CO3.

∴Moles of CO2 = Moles of Li2CO3 = 0.0207. 
PilotLPTM [1.2K]3 years ago
7 0

<u>Answer:</u> The moles of carbon dioxide produced is 0.021 moles.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of lithium carbonate = 1.53 g

Molar mass of lithium carbonate = 73.9 g/mol

Putting values in above equation, we get:

\text{Moles of lithium carbonate}=\frac{1.53g}{73.9g/mol}=0.021mol

For the given chemical reaction:

Li_2CO_3(s)+2HCl(aq.)\rightarrow 2LiCl(aq.)+H_2O(l)+CO_2(g)

As, hydrochloric acid is present in excess. So, it is considered as an excess reagent.

Lithium carbonate is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of lithium carbonate produces 1 mole of carbon dioxide

So, 0.021 moles of lithium carbonate will produce = \frac{1}{1}\times 0.021=0.021mol of carbon dioxide

Hence, the moles of carbon dioxide produced is 0.021 moles.

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Sonbull [250]
<h3>Answer:</h3>

128 g HCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Reaction Mole Ratios
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg (s) + HCl (aq) → MgCl (aq) + H₂ (g)

↓

[RxN - Balanced] 2Mg (s) + 2HCl (aq) → 2MgCl (aq) + H₂ (g)

[Given] 3.25 mol Mg

[Solve] x g HCl

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Mg → 2 mol HCl

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of HCl - 1.01 + 35.45 = 36.46 g/mol

<u>Step 3: Stoich</u>

  1. [S - DA] Set up:                                                                                                 \displaystyle 3.25 \ mol \ Mg(\frac{2 \ mol \ HCl}{2 \ mol \ Mg})(\frac{36.46 \ g \ HCl}{1 \ mol \ HCl})
  2. [S - DA] Multiply/Divide [Cancel out units]:                                                    \displaystyle 127.61 \ g \ HCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

127.61 g HCl ≈ 128 g HCl

3 0
2 years ago
Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation. The reaction is C2H2(g)+2H2(g)?C2H6(g)
Alecsey [184]

Answer:

Keq =1.50108

Explanation:

The given reactionis

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              = - 242.09kJ/mol

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           =0.406

    Keq =e0.406

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3 0
3 years ago
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Lilit [14]

Answer:

pH = 1.32

Explanation:

                 H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺

This problem involves a weak diprotic acid which we can solve by realizing they amount  to buffer solutions.  In the first  deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:

So first calculate the moles reacted and produced:

n H₂M = 0.864 g/mol x 1 mol/ 116.072 g  =  0.074 mol H₂M

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it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.

moles H₂M left = 0.074 - 0.015 = 0.059

moles HM⁻ produced = 0.015

Using the Henderson - Hasselbach equation to solve for pH:

ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325

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For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.

           

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Dafna1 [17]

<em>Answer:</em>

  • The atom have a full valence electron shell.

<em>Explanation:</em>

  • My question is that why covalent bonds take place?

Every atoms tends to from bond with another atoms in order to get nearest electronic configuration of nobel gases. They become stable when their valence shell become complete. So when covelant bond forms between atoms, share electrons to each other and stabilize themselves.

5 0
3 years ago
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At what temperature scale Fahrenheit shows double than Kelvin scale​
sergij07 [2.7K]

Answer:

-12.3 degrees F.

Originally Answered: At what temperature does the Kelvin scale read double the Fahrenheit reading? -24.6 degrees C = -12.3 degrees F.

Explanation:

8 0
3 years ago
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