Answer:
It's called "Great conjunction"
Answer:
1.0 L
Explanation:
Given data
- Initial volume (V₁): 0.35 L
- Initial concentration (C₁): 2.0 M
- Final concentration (C₂): 0.70 M
John and Alex prepared a diluted solution from a concentrated one. We can find the volume of the diluted solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₂ = C₁ × V₁ / C₂
V₂ = 2.0 M × 0.35 L / 0.70 M
V₂ = 1.0 L
Answer:
oxidation occurs at the cathode.
Explanation:
In a voltaic cell electrons move from anode to cathode. At the anode, species give up electrons. This is an oxidation reaction depicted by the oxidation half equation. At the cathode, species accept electrons and become reduced. This is depicted by the reduction half equation. In summary; in a Voltaic cell, oxidation occurs at the anode while reduction occurs at the cathode.
Answer:
88%.
Explanation:
The percentage yield of lead sulfate in this experiment is 88% if 2.53 is divided by 2.85 and multiply by 100. The percentage yield can be calculated when the experimental yield is divided by theoretical yield and then multiply by 100. The percentage yield tells us about the actual yield that is gained in the end of experiment which is lower than theoretical yield.