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never [62]
3 years ago
7

Order the relative rate of diffusion of the following gases from slowest to fastest. Kr, N, Ar, Ne.

Chemistry
2 answers:
topjm [15]3 years ago
6 0

Kr, Ar, Ne, N

https://quizlet.com/60983723/science-unit-3-test-flash-cards/

Arisa [49]3 years ago
6 0

Answer:

The increasing order relative rate of diffusion from fastest to slowest will be: N>Ne>Ar>Kr

Explanation:

Graham's diffusion law states that the rate of diffusion of gas is inversely proportional to the square root of the molecular mass of the gas. Mathematically given as:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molecular mass of the gas}}}

Higher the molecular mass slower will be the diffusion rate.In the given gases the molecular mass of Krypton, nitrogen ,argon and neon is 83.80 g/mol,14.01 g/mol,39.95 g/mol and 20.18 g/mol respectively.

Increasing order of molecular mass: Kr >Ar>Ne> N

So, increasing order relative rate of diffusion from fastest to slowest will be: N>Ne>Ar>Kr

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The following charges on individual oil droplets were obtained during an experiment similar to Millikan's. Determine a charge fo
RSB [31]

Answer:

- 1.602 x 10⁻¹⁹coulombs

Explanation:

Charge on individual oil droplet would be multiple of charge on one electron . So we will find out the minimum common factor of given individual charges that is the LCM of all the charges given.

LCM of given charges like 3.204 , 4.806 ,8.01 and 14.42 . We have neglected the power of ten( 10⁻¹⁹)  because it is  already a common factor to all.

The LCM  is 1.602 . So charge on electron is 1.602 x 10⁻¹⁹.

4 0
3 years ago
Who believed that a grain of sand could be divided indefinitely?
Ilya [14]

Answer:

Democritus

Explanation:

4 0
3 years ago
Enter an equation to show how h2po3− can act as a base with hs− acting as an acid. Express your answer as a chemical equation. I
vladimir2022 [97]

The acid - base equation between H2PO3^- and HS^- is H2PO3^- +  HS^- ⇄S^- + H3PO3.

<h3>What is an acid?</h3>

An acid is a substance that can donate hydrogen ions while a base is a substance that can accept hydrogen ion. This is the acid base definition according to Brownstead - Lowry.

To show the acid - base relationship between H2PO3^- and HS^-, we have the equation;

H2PO3^- +  HS^- ⇄S^- + H3PO3

Learn more about acids and bases: brainly.com/question/10282816

4 0
2 years ago
PLEASE SOMEONE HELP ME WITH THIIS QUESTION
sdas [7]

Answer:

The correct answer is - 5 carbon compounds due to low to high intermolecular forces between their molecules.

Explanation:

Bottle C has gas in it and we know that alkane has carbon and hydrogen only which means they have a single sigma bond between them and very low intermolecular forces in between molecules and are present mostly at gaseous state. Thus, bottle C has alkane.

Alcohols have -OH group that can form rarely two pi bonds which means they have intermediate intermolecular force whereas acids have -cooH group with a high molecular force so bottle B with liquid is alcohol and A has acid.

3 0
3 years ago
an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem
OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

P\cdot V = n\cdot R\cdot T,

\displaystyle V = \frac{n\cdot R\cdot T}{P}.

where

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the number of moles of particles in this gas,
  • R is the ideal gas constant, and
  • T is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of R will be 8.314 if P, V, and T are in SI units. Convert these values to SI units:

  • P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa;
  • V shall be in cubic meters, \rm m^{3};
  • T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K.

Apply the ideal gas law:

\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}.

4 0
3 years ago
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