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never [62]
3 years ago
7

Order the relative rate of diffusion of the following gases from slowest to fastest. Kr, N, Ar, Ne.

Chemistry
2 answers:
topjm [15]3 years ago
6 0

Kr, Ar, Ne, N

https://quizlet.com/60983723/science-unit-3-test-flash-cards/

Arisa [49]3 years ago
6 0

Answer:

The increasing order relative rate of diffusion from fastest to slowest will be: N>Ne>Ar>Kr

Explanation:

Graham's diffusion law states that the rate of diffusion of gas is inversely proportional to the square root of the molecular mass of the gas. Mathematically given as:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molecular mass of the gas}}}

Higher the molecular mass slower will be the diffusion rate.In the given gases the molecular mass of Krypton, nitrogen ,argon and neon is 83.80 g/mol,14.01 g/mol,39.95 g/mol and 20.18 g/mol respectively.

Increasing order of molecular mass: Kr >Ar>Ne> N

So, increasing order relative rate of diffusion from fastest to slowest will be: N>Ne>Ar>Kr

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If you had a sample containing 55 alpha particles, how many protons would be present in that sample? Show all necessary work.
arlik [135]
An alpha particle is a helium nucleus without the electrons - 2 neutrons and 2 protons.

So, all you would have to do is 2 x 55, which equals 110.

8 0
3 years ago
If 650. grams of C6H12O6 (FW 180.16) reacts with 650. grams of O2 (FW 32.00) in cellular respiration: C6H12O6 6 O2 --> 6 CO2
cestrela7 [59]

Answer:

O2 is limiting reactant

Explanation:

To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:

<em>Moles C6H12O6:</em>

650g * (1mol/180.16g) = 3.608 moles C6H12O6

<em>Moles O2:</em>

650g * (1mol/32g) = 20.31 moles O2

Now, for a complete reaction of 3.608 moles of C6H12O6 are required:

3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2

As there are just 20.31 moles of O2,

<h3>O2 is limiting reactant</h3>
4 0
2 years ago
Ba2+(aq)+SO42−(aq)→BaSO4(s)
adelina 88 [10]
I don’t know what the question is asking
4 0
3 years ago
If the mass of the object below is 28g, what is the density of the object below. Units are in cm below. Please round your answer
Murljashka [212]

Answer:

d = 0.93 g/cm³

Explanation:

Given data:

Mass of object = 28 g

Volume of object = 3cm×2cm×5cm

density of object = ?

Solution:

Volume of object = 3cm × 2cm ×5cm

Volume of object = 30 cm³

Density of object:

d = m/v

by putting values,

d = 28 g/ 30 cm³

d = 0.93 g/cm³

3 0
3 years ago
Leonard designed a parallel circuit to light two light bulbs. But his circuit doesn’t work. Which two items in the circuit must
klasskru [66]

Answer : When a parallel circuit is built the voltage across each of the components remains the same, also the total current passed is the equal to sum of the currents passing through each components in the circuits.


When 2 or more components are tried to be connected in parallel they maintain the same potential difference (in voltage) across their ends of the circuit.


The potential differences across the components are the observed to be same in magnitude, and they have identical polarities between them.


Then, this same voltage is applicable to all circuit components connected in parallel.


So, if each bulb is wired to the battery in a separate loop, the bulbs will be in parallel series.

3 0
3 years ago
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