Answer:
time =20s
Explanation:
Average speed = Distance/time
time = Distance / Average speed
Where Distance = 100meters and speed =5m/s
So,
time = 100m/5m/s
time =20s
Answer:
35000kg
Explanation:
the answer is 35000
F=m1v2/m2v2
m1=0.420kg
v2=2.00
m1=?
v2=6.00
F=40.0
40.0=0.420*2.00/m2*6.00
m2=0.84/240
m2=<em>3</em><em>5</em><em>0</em><em>0</em><em>0</em><em>/</em><em>/</em>
W=ΔKE , W=-5000j
KEinitial=(1/2)mv² , KEfinal=0j
ΔKE=-(1/2)mv²
-5000=-(1/2)(100kg)v²
v=10 m/s
Answer:
A. We are given t= 40s, x=1.25t²
So The horizontal distance it is from the airport will be = 1.25(40)²= 2000meters
B. y= 0.03t³
So y= 0.03(40)³= 1920m altitude
C. To find speed
We say
dx/dt=Vx= 2.5t= 100
dy/dy = 0.09t= 144
So speed= √100²+144²= 175.31m/s