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Galina-37 [17]
3 years ago
9

After the car with the dead battery is running, the cables can be disconnected in the reverse order that they were connected. wh

ile unhooking the jumper cables, the positive and negative cables almost touch and a spark jumps between the ends of the cables. this spark is caused by the movement of electrons through the air between the battery terminals. in what direction are the electrons traveling during the spark?
Physics
1 answer:
azamat3 years ago
4 0
Hi, thank you for posting your question here at Brainly.

Electricity is the flow of electrons due to a potential difference called voltage. The electrons naturally flows from a higher to a lower potential. Thus, the electrons flows from the positive to the negative terminal.
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A 2.00-kg object A is connected with a massless string across a massless, frictionless pulley to a 3.00-kg object B. Object A re
slamgirl [31]

Answer:

  • tension: 19.3 N
  • acceleration: 3.36 m/s^2

Explanation:

<u>Given</u>

  mass A = 2.0 kg

  mass B = 3.0 kg

  θ = 40°

<u>Find</u>

  The tension in the string

  The acceleration of the masses

<u>Solution</u>

Mass A is being pulled down the inclined plane by a force due to gravity of ...

  F = mg·sin(θ) = (2 kg)(9.8 m/s^2)(0.642788) = 12.5986 N

Mass B is being pulled downward by gravity with a force of ...

  F = mg = (3 kg)(9.8 m/s^2) = 29.4 N

The tension in the string, T, is such that the net force on each mass results in the same acceleration:

  F/m = a = F/m

  (T -12.59806 N)/(2 kg) = (29.4 N -T) N/(3 kg)

  T = (2(29.4) +3(12.5986))/5 = 19.3192 N

__

Then the acceleration of B is ...

  a = F/m = (29.4 -19.3192) N/(3 kg) = 3.36027 m/s^2

The string tension is about 19.3 N; the acceleration of the masses is about 3.36 m/s^2.

3 0
3 years ago
A pendulum is observed to complete 20 full cycles in 60 seconds. Determine the period and the frequency of the pendulum.
Delvig [45]

i hope i have been useful buddy.

good luck ♥️♥️

5 0
3 years ago
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How much work would be needed to raise the payload from the surface of the moon (i.e., x = r) to an altitude of 5r miles above t
Cloud [144]

Let the data is as following

mass of payload = "m"

mass of Moon = "M"

now we know that we place the payload from the position on the surface of moon to the position of 5r from the surface

So in this case we can say that change in the gravitational potential energy is equal to the work done to move the mass from one position to other

so it is given by

W = U_f - U_i

we know that

U_f = -\frac{GMm}{6r}

U_i = -\frac{GMm}{r}

now from above formula

W = -\frac{GMm}{6r} + \frac{GMm}{r}

W = \frac{5GMm}{6r}

so above is the work done to move the mass from surface to given altitude

7 0
3 years ago
Test questions!!!!!!!!
Pani-rosa [81]

Answer:

B. surface wave

8 0
3 years ago
Please give answer with solution​
UNO [17]
250 m. for a longer explanation or solution look at this article, i’m sorry.
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