Given:
Q = 9.4 kJ/(kg-h), the heat production rate
c = 4.18 J/(g-K), the heat capacity
t = 2.5 h, amount of time
Note that
c = 4.18 J/(g-K) = 4180 J/(kg-K) = 4.18 kJ/kg-K)
Consider 1 kg of mass.
Then
Qt = cΔT
where ΔT is the increase in temperature (°K)
(1 kg)*(9.4 kJ/(kg-h))*(2.5 h) = (1 kg)*(4.18 kJ/(kg-K))*(ΔT K)
23.5 = 4.18 ΔT
ΔT = 23.5/4.18 = 5.622 K = 5.622 °C
Answer: 5.62 K (or 5.62 °C)
Answer:
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Answer:
- C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)
(option D. with the proviso that the subscripts of propane's chemical formula must be corrected)
Explanation:
<em>Propane</em> is the saturated hydrocarbon, alkane, with chemical formula C₃H₈ or CH₃CH₂CH₃.
The complete combustion of the hydrocarbons yield carbon dioxide (CO₂) and water (H₂O).
The chemical equation that represents this combustion is:
- C₃H₈ (g) + O₂(g) → CO₂ (g) + H₂O (l) (skeleton equation: unbalanced)
Once you balance it, you get:
- C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)
Left side Right side
C 3 3
H 8 4×2 = 8
O 5×2 = 10 3×2 + 4 = 10
That equation corresponds to the option D. of the list, with the proviso that the subscripts of propane's chemical formula must be corrected
Answer:
The answer for 2-hexene is that the structure should have 6 carbon with a double bond beginning on the 2nd carbon atom.
The answer for 1-pentyne is that the structure should have 5 carbon with triple bond beginning on the 1st carbon atom.
Explanation:
<u>2-Hexene</u>
The structural formula for 2-hexene will have 6 carbons because the nomenclature has a -hex prefix, which stands for 6 carbons.
The -ene suffix of the nomenclature means that the organic compound is an alkene. Alkenes are hydrocarbons that contain double covalent bond and have the suffix -ene.
The double bond is on the 2 carbon atom because the nomenclature states that the double bond will be on the 2 carbon atom.
<u>1-Pentyne</u>
The structure will have 5 carbons since the -pent prefix means 5 carbons.
The structure has a triple bond because the -yne suffix means that the structure is an alkyne. An alkyne is a hydrocarbon with triple covalent bonds.
Also, the position of the triple bond is known because the nomenclature of the alkyne states that the triple bond is on the 1st carbon.
Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the required density by knowing it is calculated by dividing mass over volume:
Therefore, we plug in the given kilograms and liters to obtain:
Which shows the proper scientific notation.
Regards!
