<u>Answer</u>
5) b-c
6) a-b and
e-f
7) f-g
9) a-b = 0 m/s
c-d = 0.6667 m/s
e-f = 0 m/s
f-g = -3 m/s
10) b-c ⇒ The cart is acceleration.
e-f ⇒ The cart is moving backwards with a constant velocity.
<u>Explanation</u>
Answer
5) b-c
In the section b-c the cart is accelerating because the slope of the graph is changing. The gradient that represent velocity is increasing.
6) a-b and e-f
At this sections the distance is not changing at all. This can only mean that the cart is not moving. It is at rest.
7) f-g
At this section the slope is negative meaning the cart is moving back to where it came from.
9) a-b = 0 m/s
At a-b the cart is not moving. So the velocity is zero.
<u> c-d = 0.66667 m/s</u>
Velocity = distance / time
=(50-40)/(40-25)
= 10/15
= 0.6667 m/s
<u> e-f = 0 m/s</u>
At e-f the cart is not moving. So the velocity is zero.
<u> f-g = -3 m/s</u>
Velocity = distance / time
= (60-30)/(65-75)
= 30/-10
= - 3 m/s
10) b-c ⇒ The cart is acceleration.
e-f ⇒ The cart is moving backwards with a constant velocity.
Incomplete question. Full text is:
"<span>Give an example of a situation in which you would describe an object's position in (a) one-dimension coordinates (b) two-dimension coordinates (c) three-dimension coordinates"
Solution
(a) One dimension example: a man walking along a metal plank. We just need to specify one coordinate, the distance from the beginning of the plank.
(b) Two-dimension example: a ball moving on a circle. In this case, we need two coordinates: (x,y) to specify the position of the ball at every instant, since it is moving on a 2-D plane.
(c) The position of an airplane in the air: in this case we need 3 coordinates, the height, the latitude and the longitude of the airplane.</span>
Answer:
<h2>

</h2>
Explanation:
<u>Rule</u><u>:</u>
<h3>
Speed= Distance/ Time</h3>
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>!</em><em> </em>
A., Because speed is constant unless you stop it, or slow down <span />