Answer:
Explanation:
Given
radius of circular path
Position is given by
Differentiate 1 to angular velocity we get
Differentiate 2 to get angular acceleration
Net acceleration is the vector summation of tangential and centripetal force
Suppose the line on a distance-versus-time graph and the line on a speed-versus-time graph are both slanted straight lines going
1 answer:
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Answer:
For vector u, x component = 10.558 and y component =12.808
unit vector = 0.636 i+ 0.7716 j
For vector v, x component = 23.6316 and y component = -6.464
unit vector = 0.9645 i-0.2638 j
Explanation:
Let the vector u has magnitude 16.6
u makes an angle of 50.5° from x axis
So
Vertical component
So vector u will be u = 10.558 i+12.808 j
Unit vector
Now in second case let vector v has a magnitude of 24.5
Making an angle with -15.3° from x axis
So horizontal component
Vertical component
So vector v will be 23.6316 i - 6.464 j
Unit vector of v
Answer:
527 Hz
Solution:
As per the question:
Beat frequency of the player,
Frequency of the tuning fork, f = 523 Hz
Now,
The initial frequency can be calculated as:
when
when
But we know that as the length of the flute increases the frequency decreases
Hence, the initial frequency must be 527 Hz
Answer:
v ’= 21.44 m / s
Explanation:
This is a doppler effect exercise that changes the frequency of the sound due to the relative movement of the source and the observer, the expression that describes the phenomenon for body approaching s
f ’= f (v + v₀) / (v-)
where it goes is the speed of sound 343 m / s, v_{s} the speed of the source v or the speed of the observer
in this exercise both the source and the observer are moving, we will assume that both have the same speed,
v₀ = v_{s} = v ’
we substitute
f ’= f (v + v’) / (v - v ’)
f ’/ f (v-v’) = v + v ’
v (f ’/ f -1) = v’ (1 + f ’/ f)
v ’= (f’ / f-1) / (1 + f ’/ f) v
v ’= (f’-f) / (f + f’) v
let's calculate
v ’= (3400 -3000) / (3000 +3400) 343
v ’= 400/6400 343
v ’= 21.44 m / s