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3 years ago

13

Suppose the line on a distance-versus-time graph and the line on a speed-versus-time graph are both slanted straight lines going

through the origin. Can the two graphs be displaying the motion of the same object? Explain.

1 answer:

lesya [120]3 years ago

4 0

No, because the distance-time would show a constant velocity but the velocity-time graph shows an increasing velocity.

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About how many days in the moon’s cycle is it waxing?.

Monica [59]

Answer: 29.5 days

The waxing moon phase comprises three separate moon phases: the Waxing Crescent, First Quarter, and the Waxing Gibbous.

8 0

2 years ago

Read 2 more answers

Estimate the mass of the Great Pyramid of Giza, in tons. You make may use of the following information: the Great Pyramid is in

postnew [5]

Answer:

6005803.83105 short tons

Explanation:

The definition of density is $\rho = \frac{m}{V}$ , and the volume of a pyramid is (confusingly written on the proposal) $V=\frac{1}{3} Ah$ , so we can write:

$m=\rho V=\rho V \frac{1}{3} Ah=\rho V \frac{1}{3} s^2h$

Where s is the side of the base, being $s^2$ the area of that square.

We will write everything in S.I., and the best way to convert units is using conversion factors, for example, since 1m=100cm, we know that $\frac{1m}{100cm}=1$ , and we can use this factor to convert anything written in cm to anything written in m. Example:

$500cm=500cm\frac{1m}{100cm}=5m$

Here we just multiplied 500cm by something that is equal to 1 (as every conversion factor must), so <em>it's not doing anything but changing the units</em>.

We can use this tool like this:

$2.1\frac{g}{cm^3}=2.1\frac{g}{cm^3}(\frac{1Kg}{1000g})(\frac{100cm}{1m})^3=2100Kg/m^3$

Where we have used the fact that $1^3=1$ (<u>we can elevate any conversion factor to any number and they still will be 1</u>) and where we have placed strategically what is the numerator and what in the denominator so the units we don't want cancel out and the units we want appear.

Substituting then our values:

$m=\rho V \frac{1}{3} s^2h=(2100Kg/m^3)\frac{1}{3} (230.34m)^2(146.7m)=5448373586.96Kg$

And now we will convert to short tons using two conversion factors at the same time:

$m=5448373586.96\ Kg(\frac{1\ lb}{0.45359237\ Kg})(\frac{1\ short\ ton}{2000\ lb} )=6005803.83105\ short \ tons$

Remember, their value is 1, and we place the units to cancel the ones we don't want and keep the ones we want, here Kg cancel out, and lb cancel out, leaving the short tones.

8 0

2 years ago

Un paracaidista desciende desde 6 000 m de altura. Si la masa, con su equipo, es de 65 kg, ¿cuánto valdrá su energía potencial e

iris [78.8K]

Explanation:

PRIMERO ENCUENTRAS EL PESO DEL PARACAIDISTA

$F_{peso}$ = 65 kg( $9.80 m/s^{2}$ ) = 637 N

CON LA FÓRMULA DE LA ENERGÍA POTENCIAL

U = 637 N(6000 m - 3500 m) = 1592500 J

3 0

3 years ago

What are the names of the 2 charged particles in an atom and what are their charges

Sholpan [36]

Answer:

Protons and electrons

Explanation:

The atoms are made up of protons, neutrons, and electrons.
The physical and chemical characteristics of an atom are determined by the number of these particle composition.
The protons present in the center of an atom called the nucleus is positively charged.
The neutrons are also located in the nucleus of an atom with no charge.
The electrons has a negative charge and it is placed around the nucleus having different shells and quantum state.
The charges of the protons and electrons are denoted by +q and -q. The quantization of these charges are +1, +2, ... and -1, -2, .... etc.

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2 years ago

If the mass of each ball is 12 kg and they experience a gravitational force of magnitude 2.00

VLD [36.1K]

Answer:

${2 \times 10} - 7 = 12 {}^{2} \div x \\ x = 2 \times 10 - 7 \div 12 {}^{2}$

I'm just in jss2 but I read physics. this is what I think

7 0

2 years ago