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Serga [27]
3 years ago
13

Suppose the line on a distance-versus-time graph and the line on a speed-versus-time graph are both slanted straight lines going

through the origin. Can the two graphs be displaying the motion of the same object? Explain.
Physics
1 answer:
lesya [120]3 years ago
4 0
No, because the distance-time would show a constant velocity but the velocity-time graph shows an increasing velocity.
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78

Explanation:

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Suppose an object is launched from a point 320 feet above the earth with an initial velocity of 128 ft/sec upward, and the only
Ne4ueva [31]

Answer:

(a)Therefore the highest altitude attained by the object is =576 ft .

(b)Therefore the object takes 6 sec to fall to the ground.

Explanation:

Initial velocity: Initial velocity is a velocity from which an object starts to move.

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Final velocity: Final velocity is a velocity of an object after certain second from starting.

The final velocity is denoted by v.

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(a)

Given that u= 128 ft\sec and g = 32 ft/sec².

At highest point the velocity of the object is 0 i.e v=0

Since the displacement is opposite to the gravity.

Therefore acceleration( a)= -g = -32 ft/sec².

To find the time this to happen we use the following formula

v=u+at

Here v=0

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(b)

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To determine the time to fall we use the following formula

s=ut+\frac{1}{2} at^2

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\Rightarrow 16\times t^2=576

\Rightarrow t^2=\frac{576}{16}

\Rightarrow t^2=36

⇒t=6 sec

Therefore the object takes 6 sec to fall to the ground.

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Answer:

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