1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sauron [17]
3 years ago
13

I need help with this problem.

Physics
1 answer:
tamaranim1 [39]3 years ago
7 0

Answer:

Explanation:

Line CD

You might be interested in
An elephant lifts 7 large logs from the ground to a container 5 meters above the ground as part of a zoo demonstration. The elep
Alisiya [41]
The work done by the elephant to lift one log is the force multiplied by the height at which the log has been lifted:
W=Fh=250 N \cdot 5 m=1250 J
And so, the total work done to lift the 7 logs is 7 times the work done to lift each log:
W_t = 7 W=7 \cdot 1250 N=8750 J
5 0
2 years ago
How are galaxies organized and distributed within the universe
den301095 [7]
The galaxies aren't distributed randomly throughout the universe but they are grouped in gravitationally bound clusters.
3 0
3 years ago
Read 2 more answers
6. A car moving in a straight line at constant speed:
ddd [48]

Answer:

D. has no overall force acting on it.

Explanation:

Why?

Because in a straight line at the constant speed means the car moving in the same velocity, which is not acceleration neither deceleration, and it cannot be on a downhill slope. So the correct answer is

<h3>→ D. has no overall force acting on it.</h3>
8 0
3 years ago
What is night vision pls explain in long answers use<br> can use google
bulgar [2K]

Answer:

Night vision is the ability to see in low-light conditions. Whether by biological or technological means, night vision is made possible by a combination of two approaches: sufficient spectral range, and sufficient intensity range.

8 0
3 years ago
a car whose mass is 1000kg is traveling at a constant speed of 10m/s. Neglecting any friction how much force will the engine hav
AURORKA [14]
This next statement is a big deal.  It should be up on a board, surrounded
by flashing red and yellow lights, and hung on the wall of every Science
classroom.   Although we never see it in our daily lives, it's fundamental to
the workings of the universe, and it's also Newton's first law of motion:

<em>Without friction, it doesn't take <u>ANY</u> force to keep a moving object
moving.  </em>
<em>Force is only required to <u>change</u> the object's speed, or to
<u>change</u> the direction </em>
<em>in which it's moving.</em>

The answer to the question is:  On a level road, and neglecting any friction,
the engine doesn't have to supply ANY force to keep the car going at the
same speed.
7 0
3 years ago
Read 2 more answers
Other questions:
  • How do you find average velocity during free fall?
    8·2 answers
  • A block has acceleration a when pulled by a string. if two identical blocks are glued together and pulled with twice the origina
    9·1 answer
  • How radiowave work ​
    12·2 answers
  • Disturbances inside Earth’s core cause earthquakes. The starting point of the disturbance is called the epicenter. Why does the
    10·2 answers
  • A 90kg man is standing still on frictionless ice. His friend tosses him a 10kg ball, which has a horizontal velocity of 20m/s. A
    5·2 answers
  • A 4V source is connected across a 2μF capacitor. Find the charge on this capacitor.
    15·1 answer
  • 8 points)Antireflection coating can be used on the eyeglasses to reduce the reflection of light: a) A 100nm thick coating is app
    13·1 answer
  • A football game starts with a kickoff. If the ball is kicked with a velocity of 72 m/s 35 o to
    10·1 answer
  • For the circuit shown in the figure(figure 1) find the current through each resistor. Express your answers using two significant
    14·1 answer
  • Which states of a hydrogen atom can be excited by a collision with an electron with kinetic energy k = 12. 5 ev?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!