The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
If you wish to observe features that around the size of atoms, say 1.5×10⁻¹⁰ m, with electromagnetic radiation, the radiation must have a wavelength about the size of the atom itself.
a) If you had a microscope which was capable of doing this, what would the frequency of electromagnetic radiation be, in hertz that you would have to use?
b) What type of electromagnetic radiation would this be?
Given Information:
Wavelength = λ = 1.5×10⁻¹⁰ m
Required Information:
a) Frequency = f = ?
b) Type of electromagnetic radiation = ?
Answer:
a) Frequency = f = 2×10¹⁸ Hz
b) Type of electromagnetic radiation = X-rays
Explanation:
a) The frequency of the electromagnetic radiation is given by
f = c/ λ
Where λ is the wavelength of the electromagnetic radiation and c is the speed of light and its value is 3×10⁸ m/s
f = 3×10⁸/1.5×10⁻¹⁰
f = 2×10¹⁸ Hz
Therefore, the frequency of the electromagnetic radiation would be 2×10¹⁸ Hz.
b)
The frequency range of X-rays is 3×10¹⁶ Hz to 3×10¹⁹ Hz
The frequency 2×10¹⁸ lies in that range, therefore, the type of electromagnetic radiation is X-rays
. The initial velocity of the monkey is zero, while the distance covered is S=40 m. Therefore, we can use the following relationship to find vf, the final velocity of the monkey:
