Answer:
3.0 mol H₂O
Explanation:
Step 1: Write the balanced combustion equation
C₂H₆ + 3.5 O₂ ⇒ 2 CO₂ + 3 H₂O
Step 2: Establish the appropriate molar ratio
The molar ratio of C₂H₆ to H₂O is 1:3.
Step 3: Calculate the moles of H₂O formed from 1.0 mole of C₂H₆
1.0 mol C₂H₆ × 3 mol H₂O/1 mol C₂H₆ = 3.0 mol H₂O
Osmosis deals only with D. Water. Diffusion and Osmosis are relatively the same thing besides the fact that water is largely incorporated with the osmosis.
We have to get the maximum number of electrons in an atom that can have the given quantum numbers.
(a) The maximum number of electrons in an atom that can have quantum number n = 5, l = 3, 
= +3 is 2 (two).
(b) The maximum number of electrons in an atom that can have quantum number n = 3, l = 1, = -1 is 2 (two).
Here, n= principal quantum number, l= azimuthal quantum number and = magnetic quantum number.
l= 0 to (n-1) and = -l to +l including 0.
(a) n = 5, l = 3, = +3, this set of quantum number represents one 5f orbital which can contain maximum two electron of opposite spins.
(b) n = 3, l = 1, = -1, this set of quantum number represents one 3p orbital which can contain maximum two electron of opposite spins.
Answer: AgNO3 is the limiting reactant.
Explanation:
1) Balanced chemical equation:
<span>Given: 2AgNO3 + NiCl2 → 2AgCl + Ni(NO3)2
2) Mole ratios:
2 mol AgNO3 : 1 mol NiCl2 : 2 mol AgCl : 1 mol Ni(NO3)2
3) Convert 0.847 g of AgNO3 to moles
n = mass in grams / molar mass
molar mass = sum of the masses of all the atoms in the molecular formula
molar mass of AgNO3 = 107.9 g/mol + 14.0 g/mol + 3*16.0 g/mol = 169.9 g/mol
n = 0.847 g / 169.9 g/mol = 0.00499 mol AgNO3
4) Convert 0.650 g of NiCl2 to moles
n = mass in grams / molar mass
molar mass NiCl2 = 58.7 g/mol + 2*35.5 g/mol = 129.7 g/mol
n = 0.650 g / 129.7 g/mol = 0.00501 mol NiCl2
5) Compare the theoretical mole ratio with the actual ratio:
Theoretical mole ratio: 2 mol AgNO3 / 1 mol NiCl2
Actual ratio: 0.00499 mol AgNO3 / 0.00501 mol Ni Cl2 ≈ 1:1
Therefore, the amount of AgNO3 is half the required amount need to react with all the NiCl2, which means that the AgNO3 will react completely and there will be an excess of NiCl2. The reactant that is consumed completely while the other is left, is the limiting reactan. This is, AgNO3 is the limiting reactant.</span>
Answer:
1.20 × 10⁻³ mol e⁻
Explanation:
There is some info missing. I think this is the original question.
<em>Suppose a current of 0.880 A flows through a copper wire for 132 seconds. Calculate how many moles of electrons travel through the wire. Be sure your answer has the correct unit symbol and round your answer to significant digits.</em>
<em />
Step 1: Given data
- Intensity of the current (I): 0.880 A (= 0.880 C/s)
Step 2: Calculate the charge, in Coulomb, that travel through the wire
We will find the circulating charge (q) using the following expression.
Step 3: Calculate the moles of electrons with a charge of 116 C
We will use the relationship 1 mole of electrons = 96,486 C (<em>Faraday's constant</em>)
