First, we require the combustion equation of propane:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
We see that each mole of propane produces 4 moles of water.
Now, we calculate the moles of water required: 75 / 18.02
Moles required = 4.16
Moles of propane required for this are: 4.16 / 4 = 1.04 moles
Each mole of gas occupies 22.14 liters, so the volume of propane required are 1.04 * 22.14 = 23.03 L
23 L of propane are required
Answer:
<h3>The answer is 2.0 g/cm³</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 4 g
volume = 2 cm³
We have
We have the final answer as
<h3>2.0 g/cm³</h3>
Hope this helps you
20 B203(s) + 12180 HF(l) = 4060 BF3(g) + 609 H20(l)
The first one. observe that numerator and denominator are of same type in all other cases. but in 1st one, its length/volume which is crazy. how can one equate length to volume ? no way.
After series of conversion from one unit to another, the number of gallons was found to be 12 litres
<h3>
Density, Mass and Volume</h3>
Given Data
- Density of Sulfuric acid = 1.84 g/cm3
- Mass of Sulfuric acid = 184.33 Pounds
Conversion from pounds to Gram
1 kg ---------2.204 lb
x kg ---------184.33 lb
x = 184.33/2.204
x = 83.634 kg
hence the mass in gram = 83.634*1000
mass in gram = 83634 g
Now let us find the volume
We know that density = mass/volume
volume = mass/density
volume = 83634/1.84
volume = 45453.26 cm^3
Convert cm^3 to litres
Volume in litres = 45453.26 /1000
Volume in litres = 45.45 Litres
Convert from Litres to Gallons
1 gallon = 3.79 L
x gallons = 45.45 L
x = 45.45/3.79
x gallons = 11.99 L
Approx = 12 Litres
Learn more about density here:
brainly.com/question/1354972
