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konstantin123 [22]
3 years ago
7

Oh no... not again... Prof. Vitarelli spots Sybil running down the hall... yelling something... something about her tea cups...

Prof. Vitarelli and Prof. Snape try to hold her back. But they fail. She yells, I’ve learned another exam question from last year! Zinc metal reacts with hydrochloric acid to produce hydrogen gas and an aqueous solution of zinc(II) chloride. What is the reducing agent in this reaction? Maybe Prof. Umbridge was right in trying to remove her.
Chemistry
1 answer:
Y_Kistochka [10]3 years ago
6 0

Answer:

The reducing agent is Zn.

Explanation:

Let's consider the reaction between zinc and hydrochloric acid.

Zn(s) + 2 HCl(aq) ⇄ ZnCl₂(aq) + H₂(g)

This is a redox reaction, which can be divided in 2 half-reactions: reduction and oxidation.

In the reduction, H⁺ gains electrons and it is considered the oxidizing agent.

2H⁺ + 2 e⁻ ⇒ H₂

In the oxidation, Zn loses electrons and it is considered the reducing agent.

Zn ⇒ Zn²⁺ + 2 e⁻

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Answer: 8.45 L

Explanation:

Given that,

Initial volume (V1) = 3.5L

Initial pressure (P1) = 2.5 atm

[Since final pressure is given in torr, convert 2.5 atm to torr

If 1 atm = 760 torr

2.5 atm = 2.5 x 760 = 1900 torr

Final volume (V2) = ?

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Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law

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Learn more about anode here:

brainly.com/question/4052514

Your given question is quite incomplete here is complete question.

A voltaic cell is based on the reduction of _ Agt(aq) to Ag(s) and the oxidation of Sn(s) to Sn2+(aql) : Part 1  Include the phases of all species in the chemical equation: (aqh Anode: Sn(s) Sn?+ (aq)

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