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Natalka [10]
3 years ago
12

If hydrogen composes 11% of a 100 gram sample of water, what is the mass of the hydrogen in the sample?

Chemistry
2 answers:
RoseWind [281]3 years ago
5 0
It is going to be 11% of 100
11/100*100=11gram
svlad2 [7]3 years ago
4 0
4.8% is the correct answer I believe 
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The reaction between zinc (Zn) and hydrogen chloride (HCl) produces zinc chloride (ZnCl), hydrogen (H2) gas, and heat. If more h
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 If more   heat  is removed from the reaction the rate of reaction change as below to counter the action

The rate of the  <em>forward reaction increase</em> and produces more   <em>zinc chloride</em>


<u><em>      explanation</em></u>

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A person accidentally swallows three drops of liquid oxygen, , which has a density of 1.149 g/ml. assuming the drop has a volume
DerKrebs [107]
<span>134 ml First, let's determine how many moles of oxygen we have. Atomic weight oxygen = 15.999 Molar mass O2 = 2*15.999 = 31.998 g/mol We have 3 drops at 0.050 ml each for a total volume of 3*0.050ml = 0.150 ml Since the density is 1.149 g/mol, we have 1.149 g/ml * 0.150 ml = 0.17235 g of O2 Divide the number of grams by the molar mass to get the number of moles 0.17235 g / 31.998 g/mol = 0.005386274 mol Now we can use the ideal gas law. The equation PV = nRT where P = pressure (1.0 atm) V = volume n = number of moles (0.005386274 mol) R = ideal gas constant (0.082057338 L*atm/(K*mol) ) T = Absolute temperature ( 30 + 273.15 = 303.15 K) Now take the formula and solve for V, then substitute the known values and solve. PV = nRT V = nRT/P V = 0.005386274 mol * 0.082057338 L*atm/(K*mol) * 303.15 K / 1.0 atm V = 0.000441983 L*atm/(K*) * 303.15 K / 1.0 atm V = 0.133987239 L*atm / 1.0 atm V = 0.133987239 L So the volume (rounded to 3 significant figures) will be 134 ml.</span>
5 0
3 years ago
Read 2 more answers
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