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Ksju [112]
3 years ago
14

Hail comes straight down at a mass rate of m/Δt = 0.050 kg/s and an initial velocity of v0 = -15 m/s and strikes the roof perpen

dicularly. Unlike rain, hail usually does not come to rest after striking a surface. Instead, the hailstones bounce off the roof of the car. Suppose that the hail bounces off the roof of the car with a velocity of +15 m/s. Ignoring the weight of the hailstones, calculate the force exerted by the hail on the roof.
Physics
1 answer:
cupoosta [38]3 years ago
6 0

Answer:

F = 1.5 N

Explanation:

Let the hails are coming down with speed "v" and then rebound with the same speed in opposite direction

So here the change in the momentum of the hails is given as

\Delta P = mv - (-mv)

\Delta P = 2mv

now we know by Newton's 2nd Law

F = \frac{\Delta P}{\Delta t}

here we have

F = \frac{\Delta m}{\Delta t} (2v)

now plug in all data

F = 0.050(2\times 15)

F = 1.5 N

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Answer:

The initial velocity of the ball is 28.714 m/s

Explanation:

Given;

time of flight of the ball, t = 2.93 s

acceleration due to gravity, g = 9.8 m/s²

initial velocity of the ball, u = ?

The initial velocity of the ball is given by;

v = u + (-g)t

where;

v is the final speed of the ball at the given time, = 0

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u = gt

u = (9.8 x 2.93)

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Answer:

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