All categories

3 years ago

One similarity between work and power is that in order to calculate both you must know

Physics

2 answers:

svetoff [14.1K]3 years ago

8 0

D.) In order to calculate both of them, we must know the "FORCE" on the system.

Vlada [557]3 years ago

8 0

there is a lot of ways you can find power, and work too, but power more.

so in this case... it has to be force. i'm saying this because there is another way to find power and its: power = force x velocity

work = force x distance

do you see the similarity here? its force.

You might be interested in

Acceleration of 1.5 ms expressed in km /hr2?

V125BC [204]

You’re answer is 5 because !! :)

8 0

3 years ago

How far apart would you have to place the poles of a 1. 5 v battery to achieve the same electric field?

Zarrin [17]

To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m

The potential difference is related to the electric field by:

∆V=Ed

where,

∆V is the potential difference

E is the electric field

d is the distance

what is potential difference?

The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.

We want to know the distance the detectors have to be placed in order to achieve an electric field of

E=1v/cm=100v/cm

when connected to a battery with potential difference

∆v=1.5v

Solving the equation,we find

$d = \frac{ \:Δv}{e}$

$= \frac{1.5v}{100v/m}$

$= 1.5 \times 10 {}^{ - 2} m$

learn more about potential difference from here: brainly.com/question/28166044

#SPJ4

6 0

1 year ago

A(n) 10.1 g bullet is fired into a(n) 2.41 kg ballistic pendulum and becomes embedded in it. The acceleration of gravity is 9.8

fomenos

Answer:

$v = 186.90\,\frac{m}{s}$

Explanation:

The motion of ballistic pendulum is modelled by the appropriate use of the Principle of Energy Conservation:

$\frac{1}{2}\cdot (m_{p}+m_{b})\cdot v^{2} = (m_{p}+m_{b})\cdot g \cdot h$

The final velocity of the system formed by the ballistic pendulum and the bullet is:

$v = \sqrt{2\cdot g\cdot h}$

$v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (0.031\,m)}$

$v\approx 0.78\,\frac{m}{s}$

Initial velocity of the bullet can be calculated from the expression derived of the Principle of Momentum:

$(0.0101\,kg)\cdot v = (2.41\,kg + 0.0101\,kg)\cdot (0.78\,\frac{m}{s} )$

$v = 186.90\,\frac{m}{s}$

5 0

3 years ago

Help<br>pls give me an honest answer

Thepotemich [5.8K]

Answer:

0.0025H

Explanation:

I didn't come here to be part of this all I wanted is just information for my research

8 0

3 years ago

If a canadian plane is traveling at 500 miles/hr, how fast is this in m/s?

patriot [66]

223.52 meters per second

6 0

4 years ago