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GREYUIT [131]
3 years ago
8

One similarity between work and power is that in order to calculate both you must know

Physics
2 answers:
svetoff [14.1K]3 years ago
8 0
D.) In order to calculate both of them, we must know the "FORCE" on the system.
Vlada [557]3 years ago
8 0

there is a lot of ways you can find power, and work too, but power more.

so in this case... it has to be force. i'm saying this because there is another way to find power and its: power = force x velocity

work = force x distance

do you see the similarity here? its force.

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A 30kg uniform solid cylinder has a radius of 0.18m. if the cylinder accelerates at 0.023 rad/s^2 as it rotates about an axis th
Nuetrik [128]

Answer:

0.011 N-m

Explanation:

Given that

The mass of a solid cylinder, m = 30 kg

The radius of the cylinder, r = 0.18 m

The acceleration of the cylinder, \alpha =0.023\ rad/s^2

It rotates about an axis through its center. We need to find the torque acting on the cylinder. The formula for the torque is given by :

\tau=I\alpha

Where

I is the moment of inertia of the cylinder,

For cylinder,

I=\dfrac{mr^2}{2}

So,

\tau=\dfrac{mr^2\alpha }{2}\\\\\tau=\dfrac{30\times (0.18)^2\times 0.023 }{2}\\\\\tau=0.011\ N-m

So, the required torque on the cylinder is 0.011 N-m.

7 0
3 years ago
When a 0.1-kilogram pendulum bob reaches the top of its swing, how much kinetic energy does it have?
zvonat [6]
When ANY pendulum bob reaches the top of its swing,
it stops momentarily and then begins to drop.  At the instant
when it stops, its kinetic energy is zero.
7 0
3 years ago
You are sitting in a car that is travelling at a constant 10 m/s. How fast is your drink, sitting in the cup holder, traveling r
Ksenya-84 [330]

Here, we are required to determine how fast is you drink, sitting in the cup holder, travelling relative to the car.

  • The speed of the drink, sitting in the cup holder, relative to the car is; 0m/s

From the laws of relative motion,

  • <em>when object A and Object B are travelling with speed a and b respectively in the same direction, the speed of Object A relative to B is;. (a - b)</em>

  • <em>when object A and Object B are travelling with speed a and b respectively in the same direction, the speed of Object A relative to B is;. (a - b)when object A and Object B are travelling with speed a and b respectively in opposite directions, the speed of Object A relative to B is; (a+b)</em>

  • <em>when object A and Object B are travelling with speed a and b respectively in the same direction, the speed of Object A relative to B is;. (a - b)when object A and Object B are travelling with speed a and b respectively in opposite directions, the speed of Object A relative to B is; (a+b)when object A and Object B are travelling with speed a and b respectively in the same direction, where speed a = speed b, then the speed of object A relative to object B is; zero(0).</em>

Evidently, the scenario in the question is similar to the third scenario above. The cup, sitting in the cup holder is travelling with the car at the same constant speed 10m/s.

Therefore, the speed of the drink relative to the car is zero(0).

Read more:

brainly.com/question/20549055

7 0
2 years ago
Which of the following changes will always increase the efficiency of a thermodynamic engine? Choose all correct statements.
Ilya [14]

Answer:B,C,D

Explanation:

Thermodynamic  efficiency is given by

\eta =1-\frac{T_C}{T-H}

\eta efficiency can be increased by Keeping _c constant and increasing T_H

Keeping T_H constant and decreasing T_c

by increasing \Delta T=T_H-T_c

by decreasing \frac{T_C}{T_H} ratio          

5 0
3 years ago
Read 2 more answers
Ishani and John now try a problem involving a charging capacitor. An uncharged capacitor with C = 6.81 μF and a resistor with R
DENIUS [597]

Answer:

Q=81.72\times10^{-6}C

I=2.1\times10^{-5}A

Explanation:

The maximum charge on the capacitor will be, at the end of the process, given by the formula (and for our values):

Q=CV=(6.81\times10^{-6}F)(12V)=81.72\times10^{-6}C

The maximum current on the resistor will be, at the beginning of the process, given by the formula (and for our values):

I=\frac{V}{R}=\frac{12V}{5.8\times10^{5}\Omega}=2.1\times10^{-5}A

5 0
3 years ago
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