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2 years ago

One similarity between work and power is that in order to calculate both you must know

Physics

2 answers:

svetoff [14.1K]2 years ago

8 0

D.) In order to calculate both of them, we must know the "FORCE" on the system.

Vlada [557]2 years ago

8 0

there is a lot of ways you can find power, and work too, but power more.

so in this case... it has to be force. i'm saying this because there is another way to find power and its: power = force x velocity

work = force x distance

do you see the similarity here? its force.

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Help plzzzzzzzzzzzzzzzz!

aksik [14]

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2 years ago

What causes the weight of an object to change depending on if it is on Earth or the Moon?

Gnoma [55]

The acceleration due to gravity

Brainliest please

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2 years ago

Greyhound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but

maw [93]

${\large{\bold{\rm{\underline{Given \; that}}}}}$

★ A grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.

${\large{\bold{\rm{\underline{To\; find}}}}}$

★ The speed of the hound and the hare

${\large{\bold{\rm{\underline{Solution}}}}}$

★ The speed of the hound and the hare = 25:18

${\large{\bold{\rm{\underline{Full \; Solution}}}}}$

$\dashrightarrow$ As it's given that a grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.

So firstly let us assume a metres as the distance covered by the hare in one leap.

Ok now let's talk about 5 leaps,.! As it's cleared that the hare cover the distance of 5a metres.

But 3 leaps of the hound are equal to 5 leaps of the hare.

Henceforth, (5/3)a meters is the distance that is covered by the hound.

Now according to the question,

Hound pursues a hare and takes 5 leaps for every 6 leaps of the hare..! (Same interval)

Now the distance travelled by the hound in it's 5 leaps..!

(5/3)a × 5

25/3a metres

Now the distance travelled by the hare in it's 6 leaps..!

6a metres

Now let us compare the speed of the hound and the hare. Let us calculate them in the form of ratio..!

25/3a = 6a

25/3 = 6

25:18

5 0

2 years ago

The air temperature in a 28 in.3 container with a free sliding piston is initially measured at 45 °

sergiy2304 [10]

To solve this we assume that the gas inside is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 659.7 x 28 / 504.7

V2 = 36.60 in^3

8 0

2 years ago

a car headed north at 15 m/s accelerates for 4.25 s to reach a velocity of 28.3 m/s. What is the acceleration of the car?

Liono4ka [1.6K]

Answer:

The acceleration of the car is $3.13 m/s^2$

Explanation:

In the question it is given that car initially heads north with a velocity $15 m/s$ . It then accelerates for $4.25 s$ and in the end its velocity is $28.3 m/s$ .