2 years ago

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Physics

1 answer:

Burka [1]2 years ago

4 0

Answer:

Second option

Explanation:

"Uniform" pretty much means the same thing happens.

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Change a speed of 72.4 miles per hour to its equivalent in meters per second.

4vir4ik [10]

Answer:

Speed in meter/sec will be 32.1777 m /sec

Explanation:

We have given speed = 72.4 miles per hour

We have to convert this speed in meter per second

We know that 1 miles = 1.6 km

So 72.4 miles = 72.4×1.6= 115.84 km

We also know that 1 km = 1000 m

So 115.84 km $=115.84\times 10^3m$

We know that 1 hour = 60×60 = 3600 sec

So $72.4miles/hour=\frac{72.4\times 1600m}{3600sec}=32.1777m/sec$

7 0

3 years ago

Solve 13.004+3.09+112.947

Mashcka [7]

Answer:

The answer is 129.041

Explanation:

Because when you add desimals you need to keep them lined up and not uneven

4 0

3 years ago

Cars are safety tested to see how quickly they come to a stop under many conditions. The distance and time of one of these tests

stepladder [879]

Answer:Is C,0

Explanation:

5 0

3 years ago

Read 2 more answers

A car is traveling on a straight, level road under wintry conditions. Seeing a patch of ice ahead of her, the driver of the car

dangina [55]

Her magnitude of deceleration on the ice would be 15.126m/s

5 0

2 years ago

A person weighing 0.9 kN rides in an elevator that has a downward acceleration of 1.9 m/s^2. The acceleration of gravity is 9.8

Keith_Richards [23]

Answer:

The magnitude of the force is 0.7255kN

Explanation:

The elevator floor acts on the person with a force that is due to the gravitational acceleration less the downward acceleration of the elevator:

(force of floor F) = (mass of person m) x [ (grav. acceleration g) - (elevator acceleration a) ]

in other words, considering the elevator floor as a reference frame in the Earth's gravitational field, the person's weight decreases due to the downward acceleration, as follows:

$F = m\cdot(g-a)$

We are given the person's weight at rest, 0.9kN, from which the mass can be determined as:

$900 N = m\cdot g \implies m = \frac{900N}{9.8 \frac{m}{s^2}}$

$F = \frac{900N}{9.8 \frac{m}{s^2}}\cdot(9.8-1.9)\frac{m}{s^2}\approx 725.5N=0.7255kN$

3 0

2 years ago