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kumpel [21]
2 years ago
7

What may be expected when K > 1.0?

Chemistry
2 answers:
lora16 [44]2 years ago
4 0

The two correct statements are:

1. The concentration of one or more of the products is small

2. The reaction will proceed to the right and favor the formation of products.

LeChatelier's Principle states that when a stress is imposed on a system at equilibrium, the equilibrium will shift to counteract the change. A reduction in the number of products cause the system to respond by making more product, which leads to K>1 and products being more favorable.

timofeeve [1]2 years ago
4 0

<u>Answer:</u> The two correct statements are the concentration of one or more of the reactants is small and the reaction will proceed to the right and favor the formation of products.

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients. It is expressed as K_{eq}

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_{eq} is given as:

K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

Equilibrium constant is inversely related to the concentration of the reactants. So, if concentration of any reactants is less, the vale of K_{eq} will be more.

Conditions of K_{eq} are:

  • When K < 1; the reaction is favored to the left or in backward direction or reactants are formed more.
  • When K > 1; the reaction is favored to the right or in forward direction or products are formed more.
  • When K = 1; the reaction is in equilibrium.

Hence, the two correct statements are the concentration of one or more of the reactants is small and the reaction will proceed to the right and favor the formation of products.

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Analysis of an athletes urine found the presence of a compound with a molar mass of 312 g/mol. How many moles of this compound a
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<h3>Answer:</h3>

= 5.79 × 10^19 molecules

<h3>Explanation:</h3>

The molar mass of the compound is 312 g/mol

Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)

We are required to calculate the number of molecules present

We will use the following steps;

<h3>Step 1: Calculate the number of moles of the compound </h3>

Moles=\frac{mass}{molar mass}

Therefore;

Moles of the compound will be;

=\frac{0.030}{312g/mol}

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<h3>Step 2: Calculate the number of molecules present </h3>

Using the Avogadro's constant, 6.022 × 10^23

1 mole of a compound contains 6.022 × 10^23  molecules

Therefore;

9.615 × 10⁻5 moles of the compound will have ;

= 9.615 × 10⁻5 moles × 6.022 × 10^23  molecules

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Mass = 108 g

Explanation:

Given data:

Mass of water produced = ?

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Mass = 6 mol × 18 g/mol

Mass = 108 g

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