1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kumpel [21]
3 years ago
7

What may be expected when K > 1.0?

Chemistry
2 answers:
lora16 [44]3 years ago
4 0

The two correct statements are:

1. The concentration of one or more of the products is small

2. The reaction will proceed to the right and favor the formation of products.

LeChatelier's Principle states that when a stress is imposed on a system at equilibrium, the equilibrium will shift to counteract the change. A reduction in the number of products cause the system to respond by making more product, which leads to K>1 and products being more favorable.

timofeeve [1]3 years ago
4 0

<u>Answer:</u> The two correct statements are the concentration of one or more of the reactants is small and the reaction will proceed to the right and favor the formation of products.

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients. It is expressed as K_{eq}

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_{eq} is given as:

K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

Equilibrium constant is inversely related to the concentration of the reactants. So, if concentration of any reactants is less, the vale of K_{eq} will be more.

Conditions of K_{eq} are:

  • When K < 1; the reaction is favored to the left or in backward direction or reactants are formed more.
  • When K > 1; the reaction is favored to the right or in forward direction or products are formed more.
  • When K = 1; the reaction is in equilibrium.

Hence, the two correct statements are the concentration of one or more of the reactants is small and the reaction will proceed to the right and favor the formation of products.

You might be interested in
A 1.513 g sample of KHP (C8H5O4K) is dissolved in 50.0 mL of DI water. When the KHP solution was titrated with NaOH, 14.8 mL was
son4ous [18]

Answer:

0.501 M

Explanation:

  • KHP + NaOH → NaKP + H₂O

First we <u>convert 1.513 g of KHP into moles</u>, using its <em>molar mass</em>:

  • 1.513 g ÷ 204.22 g/mol = 7.41x10⁻³ mol = 7.41 mmol

As <em>1 mol of KHP reacts with 1 mol of NaOH</em>, in 14.8 mL of the NaOH solution there were 7.41 mmoles of NaOH.

With the above information in mind we can <u>calculate the molarity of the NaOH solution</u>:

  • 7.41 mmol / 14.8 mL = 0.501 M
3 0
3 years ago
A reaction mixture at equilibrium at 175 k contains ph2 = 0.958 atm, pi2 = 0.877 atm, and phi = 0.020 atm. a second reaction mix
Sophie [7]
 from ICE table
            H2(g) +  I2 (g )↔ 2HI(g)
 equ       0.958      0.877         0.02   first mix1
              0.621        0.621         0.101      sec mix2

Kp1 = P(HI)^2 / p(H2)*p(I2) for mix 1
       = 0.02^2 / 0.958*0.877
       = 4.8x10^-4
Kp2 = P(HI)^2 / P(H2)* P(I2) for mix 2
        = 0.101^2/ 0.621*0.621 
        = 0.0265
we can see that Kp1< Kp2 that means that the sec mixture is not at equilibrium. It will go left to reduce its products and increase reactant to reduce the Kp value to achieve equilibrium.

and the partial pressure of Hi when mix 2 reach equilibrium is:
4.8x10^-4 = P(Hi)^2 / (0.621*0.621)
∴ P(Hi) at equilibrium = 0.0136 atm



8 0
3 years ago
How are an acid and a base define and describe the nature of each based on the strength, pH, and ion concentration?
Stels [109]

here are some notes i took on acids and bases and salts...i hope this helps

3 0
3 years ago
At STP, what is the volume of 1.0 mole of carbon dioxide?
anzhelika [568]

Using ideal gas equation,

PV=nRT

Where P=pressure(atm), V=volume(L), n=number of moles of the gas, R=gas constant, 0.0821 atm L/moles K, T=temperature(K)

At STP:

P=1 atm

T=273K

n=1 as given

So using ideal gas equation,

V=nRT/P

So,

V=1*0.0821*273/1

=22.4 L

8 0
3 years ago
Read 2 more answers
The compound known as diethyl ether, commonly referred to as ether, contains carbon, hydrogen, and oxygen. A 1.751 g sample of e
fredd [130]

<u>Answer:</u> The empirical formula for the given compound is C_{4}H_{10}O

<u>Explanation:</u>

The chemical equation for the combustion of ether follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=4.159g

Mass of H_2O=2.128g

Mass of sample = 1.751 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 4.159 g of carbon dioxide, \frac{12}{44}\times 4.159=1.134g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 2.128 g of water, \frac{2}{18}\times 2.128=0.236g of hydrogen will be contained.

Mass of oxygen in the compound = (1.751) - (1.134 + 0.236) = 0.381 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = \frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.134g}{12g/mole}=0.0945moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.236g}{1g/mole}=0.236moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.381g}{16g/mole}=0.0238moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0238 moles.

For Carbon = \frac{0.0945}{0.0238}=3.97\approx 4

For Hydrogen = \frac{0.236}{0.0238}=9.91\approx 10

For Oxygen = \frac{0.0238}{0.0238}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 10 : 1

Hence, the empirical formula for the given compound is C_{4}H_{10}O

7 0
3 years ago
Other questions:
  • most scientists in wegeners day rejected his hypothesis on continental drift because he could not explain
    15·2 answers
  • The standard unit for measuring mass is the gram.<br> a. True<br> b. False
    9·2 answers
  • Given 6.98 x 10 4 power grams of iron, calculate the moles of iron present
    15·1 answer
  • how many grams of lead (2) chloride can be collected from 34.5 g sodium chloride and an excess amount of lead (2) nitrate?
    9·1 answer
  • How long is a half life for carbon 14?
    11·2 answers
  • HELP ;-;
    6·1 answer
  • Hiii pls help me to write out the ionic equation ​
    14·1 answer
  • What do these two changes have in common? Shaking up salad dressing. Adding dish soap to water in a sink
    13·1 answer
  • A balloon has a volume of 7.00 liters at a pressure of 740 mm Hg. If the temperature remains constant, at what pressure will the
    7·1 answer
  • HOW DO THE FOLLOWING COMPARE IN THE AMOUNT OF ALCOHOL THEY CONTAIN: 12 OZ. BEER(5% ALCOHOL), 12 OZ. WINE COOLER(5% ALCOHOL), 1 1
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!