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kumpel [21]
2 years ago
7

What may be expected when K > 1.0?

Chemistry
2 answers:
lora16 [44]2 years ago
4 0

The two correct statements are:

1. The concentration of one or more of the products is small

2. The reaction will proceed to the right and favor the formation of products.

LeChatelier's Principle states that when a stress is imposed on a system at equilibrium, the equilibrium will shift to counteract the change. A reduction in the number of products cause the system to respond by making more product, which leads to K>1 and products being more favorable.

timofeeve [1]2 years ago
4 0

<u>Answer:</u> The two correct statements are the concentration of one or more of the reactants is small and the reaction will proceed to the right and favor the formation of products.

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients. It is expressed as K_{eq}

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_{eq} is given as:

K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

Equilibrium constant is inversely related to the concentration of the reactants. So, if concentration of any reactants is less, the vale of K_{eq} will be more.

Conditions of K_{eq} are:

  • When K < 1; the reaction is favored to the left or in backward direction or reactants are formed more.
  • When K > 1; the reaction is favored to the right or in forward direction or products are formed more.
  • When K = 1; the reaction is in equilibrium.

Hence, the two correct statements are the concentration of one or more of the reactants is small and the reaction will proceed to the right and favor the formation of products.

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The equilibrium constant, Kp, for the following reaction is 0.497 at 500K.PCl5(g) PCl3(g) + Cl2(g)If an equilibrium mixture of t
Anestetic [448]

<u>Answer:</u> The equilibrium partial pressure of chlorine gas is 0.360 atm

<u>Explanation:</u>

For the given chemical equation:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl2(g)

The expression of K_p for above reaction follows:

K_p=\frac{p_{Cl_2}\times p_{PCl_3}}{p_{PCl_5}}

We are given:

K_p=0.497\\p_{PCl_3}=0.651atm\\p_{PCl_5}=0.471atm

Putting values in above equation, we get:

0.497=\frac{p_{Cl_2}\times 0.651}{0.471}\\\\p_{Cl_2}=0.360atm

Hence, the equilibrium partial pressure of chlorine gas is 0.360 atm

5 0
2 years ago
How many moles of NaCl must be dissolved in 0.5 L of water to make a 4 mole/L
kvv77 [185]
C = 4 mol/l
v = 0.5 l

n(NaCl)=cv

n(NaCl) = 4 mol/l · 0.5 l = 2 mol

2 moles of NaCl must be dissolved

5 0
3 years ago
A chemical plant produces ammonia using the following reaction at a very high temperature and pressure. Which design issue is mo
Lorico [155]

Answer:

D. The equipment needed to accommodate the high temperature and pressure will be expensive to produce.​

Explanation:

Hello!

In this case, for the considered reaction, it is clear it is an exothermic reaction because it produces energy; and therefore, the higher the temperature the more reactants are yielded as the reverse reaction is favored. Moreover, since the effect of pressure is verified as favoring the side with fewer moles; in this case the products side (2 moles of ammonia).

In such a way, the high pressure favors the formation of ammonia whereas the high temperature the formation of hydrogen and nitrogen and therefore, option A is ruled out. Since the high pressure shifts the reaction rightwards and the high temperature leftwards, we would not be able to know whether the reaction has ended or not because it will be a "go and come back" process, that is why B is also discarded. Now, since hydrogen and nitrogen would be the "wastes", we discard C because they are not toxic. That is why the most accurate answer would be D. because it is actually true that such equipment is quite expensive.

Best regards!

6 0
2 years ago
Which choice gives the correct oxidation numbers for all three elements in rb2so3 in the order that the elements are shown in th
vlabodo [156]
<h3>Answer:</h3>

             Rb  =  + 1

              S    =  + 4

              O   =  - 2

<h3>Explanation:</h3>

                   Oxidation states of the elements were calculated keeping in mind the basic rules of assigning oxidation states which included assignment of +1 charge to first group elements i.e. Rubidium (Rb) and assignment of -2 charge to Oxygen atom. Then the oxidation state of Sulfur was calculated as follow,

Rb₂ + S + O₃  =  0

Above zero (0) means that the overall molecule is neutral.

Putting values of Rb and O,

                                           (+1)₂ + S + (-2)₃  =  0

                                           (+2) + S + (-6)  =  0

                                           +2 + S - 6  = 0

                                           S - 6  =  -2

                                          S  =  -2 + 6

                                           S  =  + 4

7 0
3 years ago
A molecule with 14 total electrons and 12 total protons
Snowcat [4.5K]

Answer:

Explanation:

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5 0
2 years ago
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