Answer:
This point is not accelerating.
Explanation:
An object can be acted on by several forces at the same time, these forces are vector quantities (with magnitude and direction associated). The vector sum of all of the forces acting on a body is a single force called the net force when an object is in equilibrium this net force is equal to zero.
<em>According to Newton's second law of motion, the acceleration of an object as produced by a net force is directly proportional to the net's force, direction, and force and inversely proportional to the mass of the object. </em><em>This means that if the net force is zero an object will have zero acceleration.</em>
Therefore we can conclude that the sum of the three forces acting on the center point of the rope is assumed to be zero this point is not accelerating.
I hope you find this information useful and interesting! Good luck!
Through spectroscopy. Each atom in a gas absorbs and emits light at very specific and unique frequencies. Heating up a gas causes it to glow at these frequencies. If you put the light from a mercury lamp, for example, through a prism there will not be a rainbow. There will only be specific bands of light at certain colors.
On the other hand, white light comes from the sun. The inner part of the sun creates white light as it isn't just a gas state (this specific choosing of frequencies is a gaseous phenomenon) but the atmosphere of the sun is a gas. So when the white light passes through it, it absorbs specific frequencies specific to the elements in the gas. These get scattered (released at random directions) and so many of them don't reach our telescopes. So in a rainbow from stars (including the sun) have dark bands at specific frequencies. You need equipment to focus and see the spectrum closely to notice this. But the missing frequencies are the EXACT frequencies that the gas of the sun's atmosphere would release if heated in a lamp.
So based on what light is emitted (in gas bulbs) or missing from a spectrum (from stars) we can tell what elements are present there.
Given the mass of R-134a m = 300kg; Volume of the container V = 9 cu. meter; Temperature of R-134a T = 10 degrees Celsius;
Formula of specific volume : v = V / m = 9 / 300 = 0.03 cu. m / kg.
At T = 10 degrees Celsius from saturated R-134a tables, vf = 0.0007930 cu. m /kg; vg = 0.049403 cu. m/kg. We know v = vf + x (vg - vf), so 0.03 = 0.0007930 + x (0.049403 - 0.0007930), which makes x = 0.601.
Specific enthalpy of R-134a in the container is h = hf + x*hfg = 65.43 + (0.601 * 190.73). Answer is 180.0587 kJ/kg
Answer:
It's due to the distance from either ends of strings origin...
Explanation:
As we know that waves behave moving in a flow from one side to another side and this gives a prospective of motion. Suppose a wave is pinched from the near one end of a guitar then due to the distortion created by the point of tie of strings the wave super imposes and moves with a velocity v and produces a wave frequency f. as we the pinching go down to the center the wave stabilizes itself to a stationary origin right at the center and the frequency then changes accordingly as moving down on the string.
