Answer:
E = 30.37 J
Step-by-step explanation:
Given that,
The spring constant of the spring, k = 300 N/m
The spring is stretched by 0.45 m, x = 0.45 m
We need to find the elastic energy stored in the spring. The formula for the elastic energy is given by :
So, the required elastic energy is equal to 30.37 J.
Answer:
l = 24ft
Step-by-step explanation:
A = lw
360 = (x + 9)(x)
360 = x^2 + 9x
0 = x^2 + 9x - 360
0 = (x + 24)(x - 15)
x ≠ -24 (length cannot be negative)
x = 15
l = 15 + 9
l = 24ft
A + 2A = 180
3A = 180
A = 60
2A = 120A
Answer:
Step-by-step explanation:
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