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maw [93]
3 years ago
10

Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc

e DA beyond the starting line at t=0. The starting line is at x=0. Car A travels at a constant speed vA. Car B starts at the starting line but has a better engine than Car A, and thus Car B travels at a constant speed vB, which is greater than vA
How long after Car B started the race will Car B catch up with Car A?
Physics
1 answer:
kumpel [21]3 years ago
7 0

Answer:\frac{D_A}{v_B-v_A}

Explanation:

Given

car A had a head start of D_A

and it starts at x=0 and t=0

Car B has to travel a distance of D_A and d_a

where d_a is the distance travel by car A in time t

distance travel by car A is

d_a=v_A\times t

For car B with  speed v_B

d_B=D_A+d_a

v_B\times t=D_A+v_A\times t

t=\frac{D_A}{v_B-v_A}

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The maximum pressure most organisms can survive is about 1000 times the atmospheric pressure. Only small, simple organisms such
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Answer:

h = 10000 m

Explanation:

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She uses a voltmeter, that measures in volts, and an ammeter that measures in amps. Both were correctly placed in her circuit. I
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Answer:

A) the ammeter is x  

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  • voltage across R₁ (left resistor) =  0.75 V
  • voltage across the right one  = 0.3 V

C) 1.05 V

Explanation:

From the diagram attached below;

A) Assuming the homes were wired in series, and one of the homes face short circuit then all the houses would face power cut but it doesn't happen. So they must be connected in parallel.

Therefore; The ammeter is  connected in series, Hence, the ammeter is x  and the voltmeter must be z.

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