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maw [93]
3 years ago
10

Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc

e DA beyond the starting line at t=0. The starting line is at x=0. Car A travels at a constant speed vA. Car B starts at the starting line but has a better engine than Car A, and thus Car B travels at a constant speed vB, which is greater than vA
How long after Car B started the race will Car B catch up with Car A?
Physics
1 answer:
kumpel [21]3 years ago
7 0

Answer:\frac{D_A}{v_B-v_A}

Explanation:

Given

car A had a head start of D_A

and it starts at x=0 and t=0

Car B has to travel a distance of D_A and d_a

where d_a is the distance travel by car A in time t

distance travel by car A is

d_a=v_A\times t

For car B with  speed v_B

d_B=D_A+d_a

v_B\times t=D_A+v_A\times t

t=\frac{D_A}{v_B-v_A}

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What happens to gas that is not used
kvv77 [185]
the engine won't start or it sputters when it should be running perfectly. if the gasoline is old and stale, it will have lost a portion of its volatility. the lighter components of the gasoline (remember, gasoline is a mixture of different hydrocarbons) have probably evaporated off or disappeared.
3 0
2 years ago
An empty rubber balloon has a mass of 0.0120 kg. The balloon is filled with helium at 0°C, 1 atm pressure, and a density of 0.17
Anuta_ua [19.1K]

Answer:

a) F_b = 6.62 N

b) F_net = 5.583 N

Explanation:

Given:

- Conditions of He gas:  T = 0 C , P = 1 atm , ρ = 0.179 kg/m^3

- The mass of balloon m = 0.012 kg

- The radius of balloon r = 0.5 m

Find:

a)What is the magnitude of the buoyant force acting on the balloon?

b)What is the magnitude of the net force acting on the balloon?

Solution:

- The buoyant force F_b acting on the balloon is equal to the weight of the air it displaces.The mass of the displaced air ρ*V is the volume of the balloon times the density of the. Multiplying that by acceleration due to gravity gives its weight.

                                 F_b = ρ*V*g

                                 F_b = 4*ρ*g*pi*r^3 / 3

                                 F_b = 4*1.29*9.81*pi*.5^3 / 3

                                 F_b = 6.62 N

- The net force will be the difference between the balloon’s weight and the buoyant force. The weight of the balloon is the density of the helium times the volume of the balloon added to the mass of the empty balloon.

                                 F_g = ρ*V*g + m*g

                                 F_g = 4*ρ*g*pi*r^3 / 3 + 0.012*9.81

                                 F_g = 4*0.179*9.81*pi*.5^3 / 3 + 0.012*9.81

                                 F_g = 1.037 N

- The net force is the difference between weight and buoyant force

                                F_net = F_g - F_b

                                F_net = 6.62 - 1.037

                                F_net = 5.583 N

7 0
3 years ago
Oceanic lithosphere a. that is 10 million years old is cool enough to be denser than the asthenosphere, so it can sink down into
Sedaia [141]

Answer:

Option a

Explanation:

Ocean lithosphere that is 10 million years old is cold enough to be denser than the

asthenosphere so it can sink down into or through the asthenosphere

7 0
2 years ago
Coherent light of frequency f travels in air and is incident on two narrow slits. The interference pattern is observed on a dist
svp [43]

Answer:

A)        d = 6.1857 10⁻⁵ m

Explanation:

In the double-slit experiment the constructive interference is given by the expression

          d sin θ = m λ

          d =\frac{m \lambda  }{sin \theta}

let's use the relationship between speed, wavelength and frequency

          c = λ f

          λ = c / f

          λ = 3 10⁸ / 5.60 10¹²

          λ = 5.357 10⁻⁵ m

I do not know India in order of interference, we will assume that  m= 1

          d = 1  5,357 10⁻⁵ / sin 60

          d = 6.1857 10⁻⁵ m

3 0
2 years ago
A girl travels along the circumference of a circle of radius 14 m. What is her total distance travelled and displacement when sh
AysviL [449]

Answer:

87.976meters, 43.988 meters, 65.982 meters

Explanation:

Given data

Radius= 14m

Let us find the circumference of the circle

This is equivalent to the total distance covered

C= 2πr

C= 2*3.142*14

C= 87.976 meters

Hence the total distance is

87.976meters

The displacement when she has covered 1/2 the circle is

=87.976/2

=43.988 meters

The displacement when she has covered 3/4 the circle is

=87.976* 3/4

=65.982 meters

6 0
2 years ago
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