The velocity of the block at the bottom of the incline at point B

If a star’s radiation peaks in the ultraviolet region of the spectrum, what could you conclude?

PSYCHO15rus [73]

The short answer is "it is a very intense star."

3 0

3 years ago

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If we go on the top of the Mountain we will our weight increase or decrease?

erma4kov [3.2K]

Answer:

increase

Explanation:

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7 0

3 years ago

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In this circuit the resistance R1 is 7 Ω and R2 is 3 Ω. If this combination of resistors were to be replaced by a single resisto

Scilla [17]

Answer:

Series combination:

Equivalent resistance =10Ω

Parallel combination:

Equivalent resistance $=\frac{21}{10} \Omega$

Explanation:

Resistance: Resistance is the ratio of voltage to the current.

$R=\frac{V}{I}$

R = resistance

I = current

V= potential difference(voltage)

There are two types of resistance combinations.

series combination
parallel combination.

Series combination: If the ending point of one resistance is connected to the starting point of other resistance that combination is known as series combination.

If R₁,R₂ and R₃ are connected in series combination.

Then equivalent resistance = R₁+R₂+R₃

Parallel combination: If the ending point and the starting point of the all resistance are the same points that combination is known as parallel combination.

If R₁,R₂ and R₃ are connected in parallel combination.

Then equivalent resistance $\frac{1}{R}= \frac{1}{R_1}+ \frac{1}{R_2}+\frac{1}{R_3}$

Here R₁=7Ω and R₂=3Ω

If R₁ and R₂ connected in series combination

Then equivalent resistance = (7+3) Ω

=10Ω

If R₁ and R₂ connected in parallel combination

Then equivalent resistance $=\frac{1}{(\frac{1}{7} +\frac{1}{3})} \Omega$

$=\frac{21}{10} \Omega$

5 0

3 years ago

As a light wave strikes a shiny surface like a piece of polished metal, it will be

ycow [4]

It will reflect because polished metal is like glass or water it’s shiny and smooth

3 0

3 years ago

A 1-kg block is lifted vertically 1 m at constant speed by a boy. The work done by the boy is about:

Igoryamba

Answer:

$9.8\; {\rm J}$ , assuming that the gravitational field strength is $g = 9.8\; {\rm N \cdot kg^{-1}}$ .

Explanation:

Notice that both the speed and the direction of motion of this block are constant. In other words, the velocity of this block is constant.

By Newton's Second Law, the net force on this block would be $0$ . External forces on this block should be balanced. Thus, the magnitude of the (downward) weight of this block should be equal to the magnitude of the (upward) force that the boy applies on this block.

Let $m$ denote the mass of this block. It is given that $m = 1\; {\rm kg}$ . The weight of this block would be:

$\begin{aligned}\text{weight} &= m\, g \\ &= 1\; {\rm kg} \times 9.8\; {\rm N \cdot kg^{-1}} \\ &= 9.8\; {\rm N}\end{aligned}$ .

Hence, the force that the boy applies on this block would be upward with a magnitude of $F = 9.8\; {\rm N}$ .

The mechanical work that a force did is equal to the product of:

the magnitude of the force, and
the displacement of the object in the direction of the force.

The displacement of this block (upward by $s = 1\; {\rm m}$ ) is in the same direction as the (upward) force that this boy had applied. Thus, the work that this boy had done would be the product of:

the magnitude of the force that this boy exerted, $F = 9.8\; {\rm N}$ , and
the displacement of this block in the direction, $s = 1\; {\rm m}$ .

$\begin{aligned}\text{work} &= F\, s \\ &= 9.8\; {\rm N} \times 1\; {\rm m} \\ &= 9.8\; {\rm J}\end{aligned}$ .

5 0

2 years ago