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IgorC [24]
3 years ago
8

The velocity of the block at the bottom of the incline at point B

Physics
1 answer:
neonofarm [45]3 years ago
3 0
Not enough information is given to answer this question.
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A simple harmonic oscillator consists of a block of mass 45 g attached to a spring of spring constant 240 N/m, oscillating on a
Brrunno [24]

Answer:

The maximum displacement ,A= 0.047 m

Explanation:

Given that

Mass, m = 45 g= 0.045 kg

spring constant ,K= 240 N/m

Initial velocity at equilibrium ,v= 3.5 m/s

Lets take the maximum displacement is A

As we know that when the mass reached at the extreme position then the velocity of the mass will become zero.

From energy conservation

\dfrac{1}{2}KA^2=\dfrac{1}{2}mv^2

KA^2=mv^2

A=\sqrt{\dfrac{mv^2}{K}}

Now by putting the values

A=\sqrt{\dfrac{0.045\times 3.5^2}{240}}

A=0.047 m

The maximum displacement ,A= 0.047 m

4 0
3 years ago
Read 2 more answers
Which of the following is a primary source?
Anarel [89]

The answer is C :), I think.

6 0
3 years ago
Please help asap How can carbon monoxide be properly disposed? if you are right you will get brainliest
Elis [28]
The best way to treat CO poisoning is to breathe in pure oxygen. This treatment increases oxygen levels in the blood and helps to remove CO from the blood. Your doctor will place an oxygen mask over your nose and mouth and ask you to inhale.

Is that what you mean? Treat the poisoning? It’s a gas, so you can dispose of the gas. Unless you mean dispose of the detector?
6 0
3 years ago
The distance between two successive maximaof
denpristay [2]

Answer:

v = 1.224 m/s

Explanation:

given,                          

distance between the two successive maxima = 1.70 m

number of crest = 8          

time = 11 s                            

frequency is equal to number of cycle per secod

f = \dfrac{8}{11}          

f = 0.72\ Hz                

velocity of wave

v = f x λ                

v = 0.72 x 1.70        

v = 1.224 m/s          

Hence, the wave speed is equal to v = 1.224 m/s

4 0
3 years ago
Calculate the momentum of a 10kg bowling ball rolling at 2 m/s.
Helen [10]

Answer:

20 kg. m/s

Explanation:

p = mv

m = 10 kg

v = 2 m/s

p = 10 × 2

p = 20 kg m/s

5 0
3 years ago
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