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Answer:
a) see attached, a = g sin θ
b)
c) v = √(2gL (1-cos θ))
Explanation:
In the attached we can see the forces on the sphere, which are the attention of the bar that is perpendicular to the movement and the weight of the sphere that is vertical at all times. To solve this problem, a reference system is created with one axis parallel to the bar and the other perpendicular to the rod, the weight of decomposing in this reference system and the linear acceleration is given by
Wₓ = m a
W sin θ = m a
a = g sin θ
b) The diagram is the same, the only thing that changes is the angle that is less
θ' = 9/2 θ
c) At this point the weight and the force of the bar are in the same line of action, so that at linear acceleration it is zero, even when the pendulum has velocity v, so it follows its path.
The easiest way to find linear speed is to use conservation of energy
Highest point
Em₀ = mg h = mg L (1-cos tea)
Lowest point
Emf = K = ½ m v²
Em₀ = Emf
g L (1-cos θ) = v² / 2
v = √(2gL (1-cos θ))
A car with a velocity of 22 m/s is accelerated at a rate of 1.6 for 6.8s has the final velocity t be 32.88 m/s.
The acceleration means the amount of velocity changing per unit time.
The given data:
initial velocity, u = 22 m/s
time, t = 6.8 s
acceleration, a = 1.6
We will be using the equation of motion:
v = u + at
The final velocity become 32.88 m/s.
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Answer:
25
Explanation:
Given:
1 can of concentrate requires 3 cans of water
Now,
Total ounces in 200 6-ounce cans = 1200 ounces
also,
for 1 can of concentrate requires 3 cans of water
thus,
for 12 ounces can water can required = 3 × 12 ounces = 36 ounces of cans
Thus,
total ounce of juice per can = 12 + 36 = 48 ounces per can
therefore,
the number of 12-ounce cans required are =
or
=
or
the number of 12-ounce cans required are = 25