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What is the force on a 1000kg elevator that is falling freely at 9.8 m/sec^2

Advocard [28]

From Newton's second law, we know F = ma, where a is the acceleration and m is the mass in kg.

F = 1000kg * 9.8m/s = 9800N

F = 9800 N

Hope this helps!

3 0

3 years ago

In the doorknob shown above, when the handle is rotated a distance of 189 millimeters, the spindle is rotated a distance of 27 m

Alisiya [41]

If my math is right its A) 7

because 189 divided by 27 is 7

7 0

3 years ago

Read 2 more answers

David wants to experiment with the device, so he connects an ammeter into the circuit and measures 11.5 AA when the device is co

Mandarinka [93]

Answer:

2.42hours

Explanation:

To calculate the time taken to boil the cup of water, we will use the formula

Q = It where

Q is the total energy required to boil the water = 100KJ = 100,000Joules

I is the current = 11.5A

t is the time taken to boil the water

t = Q/I

t = 100,000/11.5

t = 8695.65seconds

t = 2.42hours

4 0

3 years ago

Newton’s first law of motion is often called the law of?

jeka57 [31]

Answer:

Newton's first law is often called the law of inertia.

searched it up to verify

Also welcome to brainly

6 0

3 years ago

Suppose the space shuttle is in orbit 300 km from the Earth's surface, and circles the earth about once every 90

Valentin [98]

The centripetal acceleration of the space shuttle is $9.0 m/s^2$ (0.9g)

Explanation:

The period of revolution of the space shuttle is

$T=90 min \cdot 60 = 5400 s$

From the period, we can calculate the angular speed of the space shuttle, which is given by

$\omega = \frac{2\pi}{T}=\frac{2\pi}{5400}=1.16\cdot 10^{-3} rad/s$

Now we can calculate the centripetal acceleration of the space shuttle, given by

$a=\omega^2 r$

where

$\omega=1.16\cdot 10^{-3} rad/s$ is the angular speed

$r=6.40 \cdot 10^6 m +300\cdot 10^3 m = 6.7\cdot 10^3 m$ is the distance of the shuttle from the Earth's centre (it is the sum of the Earth's radius, 6400 km, and of the altitude of the space shuttle, 300 km)

Substituting and solving, we find

$a=(1.16\cdot 10^{-3})^2(6.7\cdot 10^6)=9.0 m/s^2$

And since $g=9.8 m/s^2$ , this can be rewritten as

$a=\frac{9.0}{9.8}=0.9g$

Learn more about centripetal acceleration:

brainly.com/question/2562955

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7 0

3 years ago