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SVETLANKA909090 [29]
3 years ago
11

P 4 + 5O 2 P 4 O 10 , 1.5 moles of product was made in 30 seconds. What is the rate of reaction? 0.011 g/min 210 g/min 380 g/min

850 g/min
Chemistry
2 answers:
poizon [28]3 years ago
8 0

Answer:

850 g/min

Explanation:

Airida [17]3 years ago
6 0

Answer: 850.0 g/min.

Explanation:

  • The rate of the reaction = (ΔC/Δt) where,

ΔC is the change in concentration of reactants or products.

Δt is the change in time of the reaction proceeding.

  • The rate is needed to be calculated in (g/min).
  • We need to calculate the amount of the product in (g) via using the relation (n = mass / molar mass).
  • mass (g) = n x molar mass,
  • n = 1.5 moles and molar mass of P₄O₁₀ = 283.88 g/mol.
  • m = 1.5 x 283.88 = 425.82 g.
  • ΔC = 425.82 g and Δt = 30 s / 60 = 0.5 min.
  • The rate of the reaction = ΔC / Δt = (425.82 g / 0.5 min) = 851.64 g/min.

<em>can be approximated to 850.0 g/min.</em>

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Answer:

C_2H_6O

Explanation:

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Now, in 1 mol of CO2 we have 1  mol of C and in 1 mol of H_2O we have 1 mol of H. Additionally, if we want to calculate the moles of oxygen we need to <u>calculate the grams of C and O</u> and then do the <u>substraction</u> form the initial amount, so:

2.6~mol~CO_2\frac{1~mol~C}{1~mol~CO_2}\frac{12~g~C}{1~mol~C}=31.25~g~of~C

3.9~mol~H_2O\frac{2~mol~H}{1~mol~H_2O}\frac{1~g~H}{1~mol~H}=7.82~g~of~H

Total~grams=~31.25~+~7.82=39.08~g

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Now we can <u>convert the grams</u> of O to moles, so:

20.92~g~of~O\frac{1~mol~O}{16~g~O}=1.30~mol~O

The next step is to divide all the mol values by the <u>smallest one</u>:

O=\frac{1.30~mol~O}{1.30~mol~O}=~1

C=\frac{2.6~mol~C}{1.30~mol~O}=~2

H=\frac{7.82~mol~H}{1.30~mol~O}=6

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Answer:

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Explanation:

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Answer:

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Explanation:

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