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garik1379 [7]
3 years ago
9

Help pls 100 points and brainiest

Chemistry
2 answers:
Wittaler [7]3 years ago
7 0
The amount of salt solution is the independent variable
Fed [463]3 years ago
3 0

Answer:

The amount of salt solution.

Explanation:

so first you have to think about it as a y = mx + b function, where m and x are constants. So basically the independent variable is represented by the amount of salt solution because the health of the patient is affected by the amount of salt solution. this is how you would write it out as an equation so you can understand it better.

<em>The Health of the patient</em>   = <em>The amount of salt solution </em>+ <em>b</em>

Since <em>y</em> depends on the values of <em>m, x, </em>and <em>b,</em> The amount of salt solution would be the independent variable.

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I need to find the chemical equation
Yuri [45]

Answer:

2NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Explanation:

Knowing the names gets us: NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Balance: there are two sodiums and cyanides on the product side so add a 2 to the reactant side.

4 0
3 years ago
Which two compounds are molecules which both contain a double bond
Mademuasel [1]

Answer:

Double bond

Chemical compounds with double bonds.

Ethylene Carbon-carbon double bond.

Acetone Carbon-oxygen double bond.

Dimethyl sulfoxide Sulfur-oxygen double bond.

Diazene Nitrogen-nitrogen double bond.

Explanation:

pls mark me as brainleast and folow me

7 0
3 years ago
How are energy storage molecules affected if there is LESS carbon dioxide?
kipiarov [429]

Answer:

When there is less carbon (in the form of carbon dioxide) in abiotic matter, less carbon is available for producers making energy storage molecules. When there is more sunlight, producers can make more energy storage molecules from the carbon in carbon dioxide.

Hope this helps.

7 0
3 years ago
50 POINTS!!!! PLEASE HELP I AM BEGGING!!!!!!
polet [3.4K]
3CH4 refers to three molecules of a
compound and C3H12 refers to only one
molecule of a compound.
3CH4 and C3H12 are actually different
molecules though they contain the same
number and types of atoms. Recall that both
of them are hydrocarbons hence they
contain only hydrogen and carbon.
3CH4 refers to three molecules of methane
while C3H12 refers to one molecule of
diphenyl methane. Hence 3CH4 refers to
three molecules of a compound and C3H12
refers to only one molecule of a compound.
7 0
3 years ago
Balance the following redox reaction if it occurs in acidic solution. What are the coefficients in front of h2c2o4 and h2o in th
shusha [124]

Answer:

See explanation below

Explanation:

The overall reaction, is:

MnO4⁻(aq) + H₂C₂O₄(aq) ---------> Mn²⁺(aq) + CO₂(g)

Balancing this redox reaction means that one compound is reducting while the other is oxidizing. So, we need to separate both compounds into 2 semi equations and balance both of them, per separate and then, we can join them.

As we want to balance in acid medium, means that we need to add water and H⁺ in both reactions. Doing that we have the following:

MnO₄⁻   ---------------> Mn²⁺

In this reaction, we can clearly see that it's not balanced. To balance this semi equation, let's see the elements. In the reactans we have Mn and O, but in the products we only have Mn, the atom of oxygen where could it be? As we are doing acid medium, if in the reactants we have oxygen, this oxygen can be as products in the form of water, so we add water there.

MnO₄⁻   ---------------> Mn²⁺ + H₂O

Now, the water has hydrogen atoms, and if we are in acid medium, the hydrogen can only come from the acid medium, and in this case H⁺ so:

H⁺ + MnO₄⁻ ----------> Mn²⁺ + H₂O

Now, it's time to balance the charges. First Mn²⁺ is the lowest oxidation state of the manganese, this means that in the reactants Mn is passing from a higher state to a lower state, therefore, this compouns is reducting. How many electrons? well, in this case, we know that oxygen usually have the oxidation state -2, so the manganese would be:

(-2 * 4) + x = -1

-8 + x = -1 -------> x = +7

Therefore, manganese passes from 7+ to 2+, it's gaining 5 electrons so:

H⁺ + MnO₄⁻ + 5e⁻ ----------> Mn²⁺ + H₂O

Finally, we just balance the masses and charges:

8H⁺ + MnO₄⁻ + 5e⁻----------> Mn²⁺ + 4H₂O

Now, we just do the same thing with the other semi equation which is oxydizing. The explanation of that, is similar to this, so I'm gonna do it directly:

C₂O₄²⁻ -----------> CO₂

In this case, we can easily see that carbon is losing 2 electrons, so, let's put the 2 electrons on the product to balance the charges, and then, the masses:

C₂O₄²⁻ -----------> CO₂ + 2e⁻

C₂O₄²⁻ -----------> 2CO₂ + 2e⁻

Let's join both equations and do the sum of them:

8H⁺ + MnO₄⁻ + 5e⁻----------> Mn²⁺ + 4H₂O

C₂O₄²⁻ -----------> 2CO₂ + 2e⁻

As we can see, we do not have the same electrons on both equations, we need to equal those values so:

2 * (8H⁺ + MnO₄⁻ + 5e⁻----------> Mn²⁺ + 4H₂O)

5 * (C₂O₄²⁻ -----------> 2CO₂ + 2e⁻)

16H⁺ + 2MnO₄⁻ + 10e⁻----------> 2Mn²⁺ + 8H₂O

5C₂O₄²⁻ -----------> 10CO₂ + 10e⁻

Now, let's sum both equations:

16H⁺ + 2MnO₄⁻ + 10e⁻----------> 2Mn²⁺ + 8H₂O

5C₂O₄²⁻ -----------> 10CO₂ + 10e⁻

___________________________________

16H⁺ + 2MnO₄⁻ + 5C₂O₄²⁻ -----------> 2Mn²⁺ + 10CO₂ + 8H₂O

This would be the balanced reaction, however, let's put it as it was originally with the H2 in the C2O4 and balance it:

<h2>2MnO₄⁻ + 5H₂C₂O₄ + 6H⁺ -----------> 2Mn²⁺ + 10CO₂ + 8H₂O</h2>
7 0
3 years ago
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