n / V = P / RT = (4.77 atm) / ((0.08205746 L atm/K mol) x (118 K)) = 0.4926 mol/L
(2.016 g/mol) x (0.4926 mol/L) = 0.993 g/L
You would have 7 hydrogen and 2 oxygen atoms.
D. A ll of the above. catalyst reduces the activation energy thereby making the reaction faster. an increase in temperature increases the kinetic energy and no of collisions making reaction faster for an endothermic reaction while decrease in temperature favors an exothermic reaction.
increase in concentration increases the molecules reacting so the reaction is faster and vice versa.
To determine the mass of xenon tetrafluoride, we need to know first the number of fluorine atoms present in <span>oxygen difluoride. We need to convert first the mass into moles then make use of the relation of the elements from the chemical formula. Then, use the avogadro's number to convert it to number of atoms. Then, we do the reverse of the steps above but this time for </span><span>xenon tetrafluoride.
25.0 g OF2 ( 1 mol / 54 g ) ( 2 mol F / 1 mol OF2 ) ( 6.022 x10^23 atoms F / 1 mol F ) ( 1 mol / 6.022x10^23 atoms) ( 1 mol XeF4 / 4 mol F ) (207.3 g / 1 mol XeF4) = 47.99 g XeF4</span>
