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Paladinen [302]
3 years ago
13

Why are science safety rules important? PLZ DO NOT COPY AND PASTE

Chemistry
1 answer:
BigorU [14]3 years ago
8 0
It is important to follow them because they keep us safe when we’re doing experience we have to follow specific rules because these rules keep us safe from doing some thing that could possibly go wrong hope that helps
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Dalton's contribution was different from thatof the ancient Greek who postulated the existence of atoms. Point out the differenc
ELEN [110]

Answer: Democritus atomic theory is the ancient theory that describes the nature of matter in terms of atoms whereas Dalton atomic theory is a modern scientific theory that describes the nature of matter in terms of atoms. According to Dalton's theory, atoms are identically same, but Democritus had no idea about it. Atoms are never created nor destroyed, they just rearrange.

Explanation:

4 0
3 years ago
Alguien me da la fórmula de : Fosfuro ácido de estroncio?
natita [175]
la formula es Sr(OH)^2
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3 years ago
In an acid solution, ___litmus paper will turn__ .
Paraphin [41]
Somewhere in the  Orange to red range
6 0
3 years ago
Identify the atomic orbitals in the C-C sigma bond in ethyne (acetylene HC-triplebond-CH)
aleksley [76]

Answer:

Explanation:

A sigma bond is formed  when a hybrid orbital sp overlaps with another hybrid orbital or with s- or  p- orbital

Ethylene has a structural formula of  H - C≡ C- H

At the ground state; we have :

C    | ⇅ |     |↑ | ↑

        2s       2p

At the excited state, we have:

C    | ↑ |     |↑ | ↑ | ↑

the hybrid orbital

C = | ↑ | ↑ |

      2sp

8 0
4 years ago
2. A 10 kg ball is rolled down a rail from a height of 20 m. What is the velocity at the bottom of the
solmaris [256]

Answer:

19.8m/s

Explanation:

Given parameters:

Mass of the ball  = 10kg

Height of the rail  = 20m

Unknown:

Velocity at the bottom of the rail  = ?

Solution:

The velocity at the bottom of the rail is its final velocity.

Using the appropriate motion equation, we can find this parameter;

   V²   = U²  + 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height

  the ball was rolled from rest, U  = 0

  V²  = O²  + 2 x 9.8 x 20

 V  = 19.8m/s

3 0
3 years ago
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