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Elina [12.6K]
3 years ago
5

The force on a current-carrying wire is minimum when the current is moving at what angle to the magnetic field?

Physics
1 answer:
hammer [34]3 years ago
5 0

Answer:

Option A. 10 degrees

Explanation:

When a charged particle is placed magnetic field, it will possess magnetic force. The force acting on the particle is given by :

F=ilB\sin\theta

i and l are current and length of wire

Here,

\theta is the angle between velocity and magnetic field.

The force is minimum when the value of \sin\theta is minimum.

\sin(10)=0.17\\\\\sin(30)=0.5\\\\\sin(45)=0.707\\\\\sin(90)=1

It is clear that the value of sin(10) is minimum out of all other angles. So, the force on a current-carrying wire is minimum when the current is moving at what angle of 10 degrees to the magnetic field

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Explanation:

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For the first and second coils, we have:

R_1=\frac{\rho L}{A_1}\\R_2=\frac{\rho L}{A_2}\\\rho L=R_1A_1\\\rho L=R_2A_2\\R_1A_1=R_2A_2\\\frac{R_2}{R_1}=\frac{A_1}{A_2}

For the third and fourth coils, we have:

R_3=\frac{\rho L'}{A_3}\\R_4=\frac{\rho L'}{A_4}\\\rho L'=R_3A_3\\\rho L'=R_4A_4\\R_3A_3=R_4A_4\\\frac{R_4}{R_3}=\frac{A_3}{A_4}

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