Answer:
given,
initial velocity = 11.5 m/s
acceleration = 0.5 m/s²
time = 7 s
a) using equation of motion
v = u + a t
v = 11.5 + 0.5 × 7
v = 15 m/s
b) 

s = 92.75 m
distance traveled by racer with final velocity
d = 300 - 92.75
= 207.25 m
time spend to travel 207.25

t = 13.82 s
total time spent to travel 300m
t = 7 + 13.82
t = 20.82 s
time required to travel 300 m with initial velocity


= 26.09 s
time saved due to acceleration
t = 26.09 - 20.82 = 5.27 s
c) second racer is 5 m apart from the first one
distance traveled by the second racer till first one finishes the race


distance behind the leader
d = 300 -5 -245.676 = 49.34 m
time behind the winner

The distance covered by the body is 114.3 m
Explanation:
The work done by a force exerted on an object is given by

where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
For the object in this problem, we have
F = 350 N is the force applied
is the work done
if we assume that the force is applied parallel to the motion of the object
Solving for d, we find the distance covered by the object:

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The net force is 270 N
Explanation:
We can solve this problem by using Newton's second law, which states that the net force on an object is equal to the product between its mass and its acceleration:

where
F is the force
m is the mass
a is the acceleration
In this problem, we have
m = 90.0 kg

Substituting, we find the net force on the object:

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