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Akimi4 [234]
3 years ago
14

Two workers pull horizontally on a heavy box. but one pulls twice as hard as the other. The larger pull is directed at 21.0° wes

t of north, and the resultant of these two pulls is 460.0 N di-rectly northward. Use vector components to find the magnitude of each of these pulls and the direction of the smaller pull.

Physics
1 answer:
pantera1 [17]3 years ago
4 0

Answer:

The  magnitude of F1 is

|F1|=358.74 \ N

The magnitude of F2 is

|F2|=179.37\ N

And the direction of F2 is

\alpha = 44.214^o

Explanation:

<u>Net Force </u>

Forces are represented as vectors since they have magnitude and direction. The diagram of forces is shown in the figure below.  

The larger pull F1 is directed 21° west of north and is represented with the blue arrow. The other pull F2 is directed to an unspecified direction (red arrow). Since the resultant Ft (black arrow) is pointed North, the second force must be in the first quadrant. We must find out the magnitude and angle of this force.  

Following the diagram, the sum of the vector components in the x-axis of F1 and F2 must be zero:

\displaystyle -2F\ sin21^o+F\ cos\alpha =0

The sum of the vertical components of F1 and F2 must equal the total force Ft

\displaystyle -2F\ cos21^o+F\ sin\alpha =460

Solving for \alpha in the first equation

\displaystyle cos\alpha =\frac{2F\ sin21^o}{F}=2sin21^o

\displaystyle cos\alpha =0.717=>\alpha =44.214^o

\displaystyle F(2cos21^o+sin\alpha)=460

\displaystyle F=\frac{460}{2cos21^o+sin\alpha}

\displaystyle F=\frac{460}{2cos21^o+sin44.214^o}

\displaystyle F=179.37\ N

The  magnitude of F1 is

|F1|=2*F=358.74 \ N

The magnitude of F2 is

|F2|=179.37\ N

And the direction of F2 is

\alpha = 44.214^o

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Answer:

(a) F_g=1.62*10^{-48}N

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Explanation:

(a) We use Newton's law of universal gravitation, in order to calculate the gravitational force between electron and proton:

F_g=-G\frac{m_1m_2}{r^2}

Where G is the Cavendish gravitational constant, m_1 and m_2 are the masses of the electron and the proton respectively and r is the distance between them:

F_g=-6.67*10^{-11}\frac{N\cdot m^2}{kg^2}\frac{(9.11*10^{-31}kg)(1.67*10^{-27}kg)}{(2.5*10^{-10}m)^2}\\F_g=-1.62*10^{-48}N

The minus sing indicates that the force is repulsive. Thus, its magnitude is:

F_g=1.62*10^{-48}N

(b) We use Coulomb's law, in order to calculate the electric force between electron and proton, here k is the Coulomb constant and e is the elementary charge:

F_e=-k\frac{e^2}{r^2}\\F_e=-8.99*10^{9}\frac{N\cdot m^2}{C^2}\frac{(1.6*10^{-19}C)^2}{(2.5*10^{-10}m)^2}\\F_e=-3.68*10^{-9}N

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(1) The intensity of a sound wave is linearly proportional to the change in the pressure squared.

(2) You are able to hear sounds from farther away on a cool night because sound waves are refracted toward<u> </u><u>warmer air </u><u>near the ground.</u>

(3) When the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.

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The intensity of a sound wave is linearly proportional to the change in the pressure squared and inversely proportional to the density and the speed.

<h3>Refraction of sound waves</h3>

You are able to hear sounds from farther away on a cool night because sound waves are refracted toward warmer air near the ground.

<h3>Destructive inference</h3>

When the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.

<h3>Time taken for the heater to provide the energy</h3>

E = Power x Time

t = E/P

t = 60,000/200

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Q = 79.8 cal/g x 100 g

Q = 7,980 cal

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Q = 0.1 kg x 4184 J/kgC x (100 - 20)

<em>When water vapor condense into liquid water, temperature = 100⁰C</em>

Q = 33,472 J

Thus, the intensity of a sound wave is linearly proportional to the change in the pressure squared.

  • You are able to hear sounds from farther away on a cool night because sound waves are refracted toward<u> </u><u>warmer air </u><u>near the ground.</u>
  • When the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.
  • The time taken for the heater to provide the energy is 300 secs.
  • The total amount of heat provided to the ice sample is 7,980 cal.
  • The amount of heat required to increase the temperature of water is 33,472 J.

Learn more about intensity of sound here: brainly.com/question/17062836

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