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Digiron [165]
3 years ago
13

As your hand moves back and forth to generate longitudinal pulses in a spiral spring, your hand completes 2.91 back-and-forth cy

cles every 3.67 s. The velocity of the pulse in the spring is 0.925 cm/s. What is the wavelength? Answer in units of m.
Physics
1 answer:
Lapatulllka [165]3 years ago
8 0

Answer:

Wavelength, \lambda=0.011\ m

Explanation:

Given that,

Number of cycles in a spiral spring is 2.91 in every 3.67 s

The velocity of the pulse in the spring is 0.925 cm/s, v = 0.00925 m/s

To find,

Wavelength

Solution,

Number of cycles per unit time is called frequency of a wave. The frequency of the longitudinal pulse is,

f=\dfrac{2.91}{3.67}=0.79\ Hz

The wavelength of a wave is given by :

\lambda=\dfrac{v}{f}

\lambda=\dfrac{0.00925\ m/s}{0.79\ Hz}

\lambda=0.011\ m

So, the wavelength of the longitudinal pulse is 0.011 meters. Hence, this is the required solution.

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Explanation:

cellulose and pectin are present on the cells of collenchyma...

8 0
3 years ago
A piece of string 2 meters and has a mass of 5g. On one end of the string hangs a 200 g mass. Find the tension of the string and
viktelen [127]

Explanation:

It is given that,

Length of the string, l = 2 m

Mass of the string, m=5\ g=5\times 10^{-3}\ kg

Hanged mass in the string, m'=200\ g=0.2\ kg

1. The tension in the string is given by :

T=m'g

T=0.2\times 9.8

T = 1.96 N

2. Velocity of the transverse wave in the string is given by :

v=\sqrt{\dfrac{T}{M}}

m = M/l

v=\sqrt{\dfrac{Tl}{m}}

v=\sqrt{\dfrac{1.96\times 2}{5\times 10^{-3}}}

v = 28 m/s

Hence, this is the required solution.

4 0
3 years ago
A set of charged plates 0.00262 m apart has an electric field of 155 N/C between them. What is the potential difference between
mylen [45]

Answer: The potential difference between the plates = 0.4061V

Explanation:

Given that the

Electric field strength E = 155 N/C

Distance d = 0.00262 m

From the definition of electric field strength, is the ratio of potential difference V to the distance between the plates. That is

E = V/d

Substitute E and d into the above formula

155 = V/0.00262

Cross multiply

V = 155 × 0.00262

V = 0.4061 V

The potential difference between the plates is 0.4061 V

5 0
3 years ago
Technician A says that galvanic activity is the result of a poor ground connection. Technician B says that electrolysis can occu
Drupady [299]

Answer:

Only B is correct.

Explanation:

Electrolysis and galvanic activity are two different ways of the passage of electricity. Electrolysis occurs at a spontaneous reaction, and galvanic activity needs an external force to happen.

For example, a cell works by a redox reaction, in which a material reduces (gain electrons), and the other oxides (loses electrons). As higher is the standard reduction potential of a material, as easy is to it to reduces. Thus, if a cell works with the reduction happens with the material with low standard reduction potential, then it works by galvanic activity.

When electronics are connected to the house system, it's necessary to do the ground connection, which will allow the electrons that are dissipated to go to the earth. So, it is done incorrectly, the electrons flow to the equipment, which they natural path. So, the electrolysis can occur with a poor ground connection.

7 0
4 years ago
A mail carrier leaves the post office and drives 2.00 km to the north. He then drives in a direction 60.0° south of east for 7.00
Oxana [17]

Answer:

12.97 km

Explanation:

In order to find the resultant displacement, we have to resolve each of the 3 displacements along the x and y direction.

Taking north as positive y direction and east as positive x-direction, we have:

- Displacement 1: 2.00 km to the north

So

A_x = 0\\A_y = +2.00 km

- Displacement 2: 60.0° south of east for 7.00 km

So

B_x=(7.00)(cos (-45^{\circ}))=4.95 km\\B_y = (7.00)(sin (-45^{\circ}))=-4.95 km

- Displacement 3: 9.50 km 35.0° north of east

So

C_x=(9.50)(cos 35^{\circ})=7.78 km\\C_y=(9.50)(sin 35^{\circ})=5.45 km

So the net displacement along the two directions is:

R_x=A_x+B_x+C_x=0+4.95+7.78=12.73 km\\R_y=A_y+B_y+C_y=2.00+(-4.95)+5.45=2.50 km

So, the  distance between the initial and final position is equal to the magnitude of the net displacement:

R=\sqrt{R_x^2+R_y^2}=\sqrt{12.73^2+2.50^2}=12.97 km

7 0
3 years ago
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