Explanation:
cellulose and pectin are present on the cells of collenchyma...
Explanation:
It is given that,
Length of the string, l = 2 m
Mass of the string, 
Hanged mass in the string, 
1. The tension in the string is given by :


T = 1.96 N
2. Velocity of the transverse wave in the string is given by :

m = M/l


v = 28 m/s
Hence, this is the required solution.
Answer: The potential difference between the plates = 0.4061V
Explanation:
Given that the
Electric field strength E = 155 N/C
Distance d = 0.00262 m
From the definition of electric field strength, is the ratio of potential difference V to the distance between the plates. That is
E = V/d
Substitute E and d into the above formula
155 = V/0.00262
Cross multiply
V = 155 × 0.00262
V = 0.4061 V
The potential difference between the plates is 0.4061 V
Answer:
Only B is correct.
Explanation:
Electrolysis and galvanic activity are two different ways of the passage of electricity. Electrolysis occurs at a spontaneous reaction, and galvanic activity needs an external force to happen.
For example, a cell works by a redox reaction, in which a material reduces (gain electrons), and the other oxides (loses electrons). As higher is the standard reduction potential of a material, as easy is to it to reduces. Thus, if a cell works with the reduction happens with the material with low standard reduction potential, then it works by galvanic activity.
When electronics are connected to the house system, it's necessary to do the ground connection, which will allow the electrons that are dissipated to go to the earth. So, it is done incorrectly, the electrons flow to the equipment, which they natural path. So, the electrolysis can occur with a poor ground connection.
Answer:
12.97 km
Explanation:
In order to find the resultant displacement, we have to resolve each of the 3 displacements along the x and y direction.
Taking north as positive y direction and east as positive x-direction, we have:
- Displacement 1: 2.00 km to the north
So

- Displacement 2: 60.0° south of east for 7.00 km
So

- Displacement 3: 9.50 km 35.0° north of east
So

So the net displacement along the two directions is:

So, the distance between the initial and final position is equal to the magnitude of the net displacement:
